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Ilia_Sergeevich [38]
3 years ago
13

Is there anyone here that knows how to solve quadratic equations using the quadratic formula?​

Mathematics
2 answers:
Kay [80]3 years ago
7 0

Answer:

the quadratic formula is x = (-b +_ √b^2 -4ac)/2a

find a, b, and c by this: ax^2 +bx + c = 0

and plug the value into the quadratic formula

Ann [662]3 years ago
5 0

Answer:

Me, I just learned it, I can help

Step-by-step explanation:

Formula:

ax^2 + bx + c

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The graph represents a functionE(t). Describe why the graph represents a function. Identify the
barxatty [35]

Answer:

Domain: [0, ∞)

Range: [7850, ∞)

Step-by-step explanation:

A function is defined by the set of ordered pairs having different output values for every input value.

In the graph attached, for every input value (x-coordinates) there is a unique output (y-coordinates) value.

Therefore, graph represents a function.

Domain of the given function → [0, ∞)

Range of the function → [7850, ∞)

6 0
3 years ago
PLEASE HELP!! I do not understand this. And can you explain it for me when I use it again?
damaskus [11]
Let's start b writing down coordinates of all points:
A(0,0,0)
B(0,5,0)
C(3,5,0)
D(3,0,0)
E(3,0,4)
F(0,0,4)
G(0,5,4)
H(3,5,4)

a.) When we reflect over xz plane x and z coordinates stay same, y coordinate  changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.

A(0,0,0)
Reflecting
A(0,0,0)

B(0,5,0)
Reflecting
B(0,-5,0)

C(3,5,0)
Reflecting
C(3,-5,0)

D(3,0,0)
Reflecting
D(3,0,0)


b.)
A(0,0,0)
Moving
A(-2,-3,1)

B(0,-5,0)
Moving
B(-2,-8,1)

C(3,-5,0)
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C(1,-8,1)

D(3,0,0)
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7 0
3 years ago
Please help math
Naddika [18.5K]
   
\displaystyle\\
15(2a - 2) = 5(a^2 -1) \\  \\ 
30a - 30 = 5a^2-5\\\\
-5a^2 + 30a -30 + 5 =0\\\\
-5a^2 + 30a -25 =0 ~~~~~\Big| \times (-1) \\\\
5a^2 - 30a +25 = 0~~~~~\Big| : 5 \\\\
a^2 - 6a +5 = 0 \\  \\ 
a_{12}= \frac{-b\pm \sqrt{b^2-4ac}}{2a}= \frac{6\pm \sqrt{36-20}}{2}= \frac{6\pm \sqrt{16}}{2}=\frac{6\pm 4}{2}= \boxed{3\pm 2} \\  \\ 
a_1 = 3+ 2 = \boxed{5}\\\\
a_2 = 3-2 = \boxed{1}



8 0
3 years ago
Read 2 more answers
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Olenka [21]

Answer:

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Step-by-step explanation:

I don't know if that is right but sorry if it is wrong but I would check with your teacher or someone for help

6 0
3 years ago
60 dollars for 12 hamburgers how much dollars per hamburger
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5. 60/12 is 5 :) hope this helps
6 0
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