<span>For this case we have the following expression:
</span>

<span> We are going to make the following change of variables:
</span>

<span>Rewriting the expression we have:
</span>

<span>Factoring the expression we have:
</span>

<span>Canceling similar terms we have:
</span>

<span>Returning the change we have:
</span>

<span> The resctrictions of the function are those that make the denominator equal to zero.
We have then:
</span>

<span>
Answer: The simplified expression is: </span>
<span>
The restrictions are: </span>
Using the midpoint formula, the coordinates of endpoint H are (4, -6).
<h3>The Midpoint Formula</h3>
The midpoint formula is given as: 
<em>Where</em>,
= coordinates of the midpoint
= coordinates of the first point
= coordinates of the second point
Given the following:
= M( 6,-4)
= G(8,-2)
= H(?, ?)
Plug in the values into the midpoint formula

Solve for the x-coordinate and y-coordinate separately



Therefore, using the midpoint formula, the coordinates of endpoint H are (4, -6).
Learn more about midpoint formula on:
brainly.com/question/13115533
Answer:
9.00 square units
Step-by-step explanation:
The width of the interval is 4 − 0 = 4. Divided by 4 equal subintervals, the width of each subinterval is 4/4 = 1.
The subintervals are:
0 ≤ x ≤ 1
1 ≤ x ≤ 2
2 ≤ x ≤ 3
3 ≤ x ≤ 4
MRAM is midpoint rectangular approximation method. So we use the midpoints of each interval to find the height of the rectangle:
f(0.5) = (0.5)² − 4(0.5) + 5 = 3.25
f(1.5) = (1.5)² − 4(1.5) + 5 = 1.25
f(2.5) = (2.5)² − 4(2.5) + 5 = 1.25
f(3.5) = (3.5)² − 4(3.5) + 5 = 3.25
So the total approximate area is:
A = 3.25 + 1.25 + 1.25 + 3.25
A = 9.00
Graph: desmos.com/calculator/x8dcibqszo