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alexandr402 [8]
3 years ago
5

The angle with measure between 0 and

Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

43333334

trrrrthhhffhhff

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A parabola y=1/2x^2-4x+21 can you help me find the vertex form of this parabola please and thank you :)
ale4655 [162]
Ok 
First factor out the first 2 terms as follows:-

y  = 1/2(x^2 - 8x) + 21

Now complete the square on x^2 - 8x:-

y = 1/2[ (x - 4)^2 - 16] + 21

y = 1/2(x - 4)^2 - 8 + 21

y = 1/2(x - 4)^2 + 13   Answer


3 0
3 years ago
PLS ANSWER ITS URGENT
matrenka [14]

Answer:

The length of the ramp must be at least 14.71 feet

Step-by-step explanation:

Given

BC = 2.3ft

\theta = 9^\circ

<em>See attachment for complete figure</em>

Required

Length of the ramp (z)

To do this, we consider sin of angle A (\theta).

So, we have:

sin\theta = \frac{Opposite}{Hypotenuse}

This gives:

sin(9)= \frac{2.3}{z}

Make z the subject

z= \frac{2.3}{sin(9)}

z = \frac{2.3}{0.1564}

z = 14.71 ft

<em>The length of the ramp must be at least 14.71 feet</em>

6 0
3 years ago
A study has demonstrated that the more television a person watches, the lower that person’s level of physical fitness. However,
ad-work [718]

Answer:

Option D

Step-by-step explanation:

The most valid conclusion here is that the fact that running on a treadmill allows for a greater physical fitness with the television watching deterring the effect of the exercise. In as much as he only watches TV when running, it is not enough to conclude that TV can cause less physical fitness for Pablo.

7 0
3 years ago
6. Number of passengers who arrive at the platform in an Amtrack train station for the 2 pm train on a Saturday is a random vari
Aleks04 [339]

Answer:

99.7%

Step-by-step explanation:

Mean number of passengers (μ) = 180 passengers

Standard deviation (σ) = 20 passengers

The number of standard deviation from the mean for the lower and upper bounds of the 120 to 240 passengers intervals are:

L = \frac{180-120}{20} =3\\U = \frac{240-180}{20} =3

Therefore, all of the data is within 3 standard deviations from the mean. According to the empirical rule, 99.7% of the data is within 3 standard deviations from the mean. Therefore, we can assert with a 99.7% probability  that there will be between 120 and 240 passengers.

4 0
3 years ago
Basic Computation: Testing M1 2 M2 A random sample of 49 measurements from a population with population standard deviation 3 had
Elenna [48]

Answer:

The sample statistics follows a standard normal distribution since the sample size are large enough.

Step-by-step explanation:

Given that:

<u>First population:</u>

Sample size n_1 = 49

Population standard deviation \sigma_1  = 3

Sample mean \overline x _1= 10

<u>Second population:</u>

Sample size n_2 = 64

Population standard deviation \sigma_2= 4

Sample mean \overline x_2= 12

The sample statistics follows a standard normal distribution since the sample size are large enough.

The null and alternative hypotheses can be computed as:

\mathbf{H_o:\mu_1=\mu_2}

\mathbf{H_1:\mu_1\ne\mu_2}

Level of significance  = 0.01

Using the  Z-test statistics;

Z = \dfrac{\overline x_1 - \overline x_2}{\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}}

Z = \dfrac{10- 12}{\sqrt{\dfrac{3^2}{49} + \dfrac{4^2}{64}}}

Z = \dfrac{-2}{\sqrt{\dfrac{9}{49} + \dfrac{16}{64}}}

Z = \dfrac{-2}{\sqrt{0.18367 +0.25}}

Z = \dfrac{-2}{\sqrt{0.43367}}

Z = \dfrac{-2}{0.658536}

Z = - 3.037

Z \simeq - 3.04

The P-value = 2P (z < -3.04)

From the z tables

= 2 × (0.00118)

= 0.00236

Thus, since P-value is less than the level of significance, we fail to reject the null hypotheses H_o

5 0
3 years ago
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