The angle with measure between 0 and

kykrilka [37]

Answer:

$opposite\approx 70.02$

Step-by-step explanation:

The triangle in the given problem is a right triangle, as the tower forms a right angle with the ground. This means that one can use the right angle trigonometric ratios to solve this problem. The right angle trigonometric ratios are as follows;

$sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}$

Please note that the names ( $opposite$ ) and ( $adjacent$ ) are subjective and change depending on the angle one uses in the ratio. However the name ( $hypotenuse$ ) refers to the side opposite the right angle, and thus it doesn't change depending on the reference angle.

In this problem, one is given an angle with the measure of (35) degrees, and the length of the side adjacent to this angle. One is asked to find the length of the side opposite the (35) degree angle. To achieve this, one can use the tangent ( $tan$ ) ratio.

$tan(\theta)=\frac{opposite}{adjacent}$

Substitute,

$tan(35)=\frac{opposite}{100}$

Inverse operations,

$tan(35)=\frac{opposite}{100}$

$100(tan(35))=opposite$

Simplify,

$100(tan(35))=opposite$

$70.02\approx opposite$

4 0

3 years ago

May u guys help me jus me out 5 ez questions for u guys to help me with

Elena-2011 [213]

Answer:

1. -29/156 2. 38/45 3. 29/45 4. 113/24 or about 4.7 5. 457/1, 914/2, 1371/3

Step-by-step explanation:

3/13 - 5/12 can be simplified to 36/156 - 65/156. Subtract this and you get -29/156

4/9 + 2/5 can be simplified to 20/45 + 18/45. Add this and you get

38/45

5/8 - 2/9 can be simplified to 45/72 - 16/72. Subtract this and you get

29/45

3 1/2 + 2 5/12 can be first made irrational to 7/2 + 29/24. This can be simplified to 84/24 + 29/24

113/24 or about 4.7

Not sure about the 457, but to convert it, you multiply it by whatever denominator you have. For example

1x457 = 457/1

2x457 = 914/2

And finally 3x457 = 1371/3

3 0

3 years ago

Any help is appreciated:) God blast it the photo didn’t load

mart [117]

... what is the question lol

6 0

4 years ago

Suppose that each semester at a particular community college Manuel has to pay $1478 in tuition and $121 in fees.

Kamila [148]

Answer:

Step-by-step explanation:

Let x be time, in semesters, remaining before Manuel graduates. We find that Manuel's expenses are:

$1478/semester in tuition, and

$121/semester in fees

1. x semesters remaining: fees

Remaining cost for fees, y, is the product of the fee times the number of semesters, x:

y =($121/semester)*x

y = ($121)*x

2. x semesters remaining: tuition

Remaining cost, y, is the product of the tuition (times the number of semesters, x.

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

3. x semesters remaining: tuition and fees

Remaining cost, y, is the sum of the products of the tuition (times the number of semesters, and the fees (tix.

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

5 0

1 year ago

Janae' is buying food for a party. She is buying a cheese tray for $4.50 and a few pounds of fruit for

bogdanovich [222]

Answer:

0.67

Step-by-step explanation:

5 0

3 years ago