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Nimfa-mama [501]
3 years ago
11

Which rate can you set StartFraction 7 miles Over 1 hour EndFraction equal to in order to find the distance traveled in 49 hours

at 7 miles per hour?
StartFraction 7 hours Over question mark miles EndFraction
StartFraction 49 hours Over question mark miles EndFraction
StartFraction question mark miles Over 7 hours EndFraction
StartFraction question mark miles Over 49 hours EndFraction
Mathematics
2 answers:
liberstina [14]3 years ago
8 0

Answer:

D.

Explanation:

Can you please give me Brainliest?

svet-max [94.6K]3 years ago
6 0

Answer (It should be D, or     ? miles

                                                 ------------

                                                 49 hours

Step-by-step explanation:

If i'm wrong then oh-well i took my unit test online then got the answer wrong so i could see which one was correct before i actually took the unit test... hope i'm correct for you..this is correct on my unit test practice!

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Marshall lives 2300 yards from school and 1500 yards from the pharmacy
WINSTONCH [101]

Answer:

the answer is the pharmacy bc added 2300+1500 and it gave me 3800 and if u subtract 3800-2300=1500 witch means he lives closer to the pharmacy

hoped this helped (let me know if it did) :)

8 0
3 years ago
Sydney's car used 1/ 3/5
sleet_krkn [62]

Answer:

Sydney car can go 44.4 miles on gallon

5 0
3 years ago
In an arithmetic sequence, a_17 = -40 and a_28 = -73. Please explain how to use this information to write a recursive formula fo
Vinvika [58]

An arithmetic sequence

a_1,a_2,a_3,\ldots,a_n,\ldots

is one in which consecutive terms of the sequence differ by a fixed number, call it <em>d</em>. This means that, given the first term a_1, we can build the sequence by simply adding <em>d</em> :

a_2=a_1+d

a_3=a_2+d

a_4=a_3+d

and so on, the general pattern governed by the recursive rule,

a_n=a_{n-1}+d

We can exploit this rule in order to write any term of the sequence in terms of the first one. For example,

a_3=a_2+d=(a_1+d)+d=a_1+2d

a_4=a_3+d=(a_1+2d)+d=a_1+3d

and so on up to

a_n=a_1+(n-1)d

In this case, we're not given the first term right away, but the 17th. But this isn't a problem; we can use the same exploit to get

a_{18}=a_{17}+d

a_{19}=a_{17}+2d

a_{20}=a_{17}+3d

and so on, up to the next term we know,

a_{28}=a_{17}+11d=-40+11d

(Notice how the subscript of <em>a</em> on the right and the coefficient of <em>d</em> add up to the subscript of <em>a</em> on the left.)

The 28th term is -73, so we can solve for <em>d</em> :

-73=-40+11d\implies -33=11d\implies d=-3

To get the first term of the sequence, we use the rule found above and either of the known values of the sequence. For instance,

a_{17}=a_1+16d\implies-40=a_1-16\cdot3\implies a_1=8

Then the recursive rule for this particular sequence is

\begin{cases}a_1=8\\a_n=a_{n-1}-3&\text{for }n>1\end{cases}

7 0
3 years ago
Please help as fast as you cannn
hodyreva [135]

Answer:

-43 < -35

(Negative 43 is less than negative 35).

8 0
3 years ago
Rewrite 5\11 and 3\7 so that they have common denominator
Veseljchak [2.6K]

Answer:

It would be 35/77 and 33/77

Step-by-step explanation:

You multiply the denominators until they are equal

5 0
3 years ago
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