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Nimfa-mama [501]
3 years ago
11

Which rate can you set StartFraction 7 miles Over 1 hour EndFraction equal to in order to find the distance traveled in 49 hours

at 7 miles per hour?
StartFraction 7 hours Over question mark miles EndFraction
StartFraction 49 hours Over question mark miles EndFraction
StartFraction question mark miles Over 7 hours EndFraction
StartFraction question mark miles Over 49 hours EndFraction
Mathematics
2 answers:
liberstina [14]3 years ago
8 0

Answer:

D.

Explanation:

Can you please give me Brainliest?

svet-max [94.6K]3 years ago
6 0

Answer (It should be D, or     ? miles

                                                 ------------

                                                 49 hours

Step-by-step explanation:

If i'm wrong then oh-well i took my unit test online then got the answer wrong so i could see which one was correct before i actually took the unit test... hope i'm correct for you..this is correct on my unit test practice!

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Y = mx + b
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3 years ago
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A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 614 babies bo
MissTica

Answer:

The number of newborns who weighed between 1614 grams and 5182 grams was of 586.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean weight was 3398 grams with a standard deviation of 892 grams.

This means that \mu = 3398, \sigma = 892

Proportion that weighed between 1614 and 5182 grams:

p-value of Z when X = 5182 subtracted by the p-value of Z when X = 1614.

X = 5182

Z = \frac{X - \mu}{\sigma}

Z = \frac{5182 - 3398}{892}

Z = 2

Z = 2 has a p-value of 0.9772

X = 1614

Z = \frac{X - \mu}{\sigma}

Z = \frac{1614 - 3398}{892}

Z = -2

Z = -2 has a p-value of 0.0228

0.9772 - 0.0228 = 0.9544.

Out of 614 babies:

0.9544*614 = 586

The number of newborns who weighed between 1614 grams and 5182 grams was of 586.

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3 years ago
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so the y intercept is 2 and the slope will be going upwards :)
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