Given:
The figure of a hexagon ABCDEF.
To find:
The perimeter of hexagon is ABCDEF.
Solution:
Distance formula:
From the given figure, it is clear that the vertices of the given figure are A(-6,9), B(5,9), C(8,1), D(2,-6), E(-3,-6) and F(-9,1). We get FA=CB and EF=DC
Using distance formula, we get
Similarly,
Now, the perimeter of the given hexagon is:
Therefore, the perimeter of the given hexagon is 51.527.
Wow um this is awkward i dont know this either but you cant be mad because im only 10
Answer:
C
Step-by-step explanation:
Median of triangle: It is a line segment joining a vertex to the midpoint of the opposite side.
Consider ΔABC, point F id the midpoint of line segment AB and E is the midpoint of luine segment AC.
Draw line segments FC and BE(medians of triangle). G is the point where line segment FC and BE meet. Now, Join AG.
Let H be the point outside the ΔABC and AG passs through the point H such that AG intersects BC at D. BH and HC are dashed lines.
We need to show that D is the midpoint of BC. The correct logical order for proof will be:
III. GC is parallel to line segment BH and line segment BG is parallel to line segment HC.
IV. Line segment FG is parallel to line segment BH and line segment GE is parallel to line segment HC.
I. BGCH is a parallelogram as opposite sides are parallel (from III.)
II. Since, diagnols of a parallelogram bisect each other. Henc, we get BD=DC.
Therefore, D is mid pont of BC.
It implies that AD is also a median.
Hence, all the three medians that are: BE,FC and AD passes through a common vertex G.
(5×2)= 10 (3×15)=45
(5×2)×(3×15)=405
7x8=56 (area of the rectangle of the “house” shape)
11-8=3
7x3=21x1/2 (how to find area of the triangle)
10.5
So the answer is 10.5 cm2 (centimeters squared)