Answer: 2145 ²
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given

Required
Find a
Take log of both sides

Apply law of logarithm

Divide both sides by a

Multiply both sides by -9

Apply law of logarithm

Cancel out log

Rewrite as:

Apply law of indices


Answer:
Step-by-step explanation:
If the zero occur when x={5, -2, -1} then the equation must be
(x-5)(x+2)(x+1) if expansion is desired
(x^2-3x-10)(x+1)
x^3+x^2-3x^2-3x-10x-10
x^3-2x^2-13x-10