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3 years ago

Last Wednesday it snowed 3 1/4 in. On Sunday it snowed 3 4/5 in. On which day did it snow more? How much more?

2 answers:

7 0

let's firstly convert the mixed fractions to improper fractions. and then let's make them with the same denominator by simply <u>multiplying each other by the other's denominator</u>.

$\bf \stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}~\hfill \stackrel{mixed}{3\frac{4}{5}}\implies \cfrac{3\cdot 5+4}{5}\implies \stackrel{improper}{\cfrac{19}{5}} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \textit{now let's \underline{multiply each other by the other's denominator}} \\\\\\ \cfrac{13}{4}\cdot \cfrac{5}{5}\implies \cfrac{65}{20}\qquad \qquad \qquad \cfrac{19}{5}\cdot \cfrac{4}{4}\implies \cfrac{76}{20}~\hfill \cfrac{65}{20}$

damaskus [11]3 years ago

4 0

3 4/5 because when you make the denominators equal by multiplying 1/4 by 5 on both sides and 4/5 by 4 and both sides you will get 5/20 and 16/20

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Read 2 more answers

Describe the translation. y = (x-5)squared +5 - y = (x-))squared +0

vovangra [49]

In functions; translations are used to move lines, points or shapes across the graph (i.e. up, down, right or left).

The translation from $y = (x - 5)^2 +5$ to $y = (x - 0)^2 +0$ is to shift $y = (x - 5)^2 +5$ to the left by 5 units and then downward by 5 units

The given parameters are:

$y = (x - 5)^2 +5$

$y = (x - 0)^2 +0$

Assume the first point is: $y = (x - 5)^2 +5$

While the second is: $y = (x - 0)^2 +0$

The first point is first shifted left by 5 units

The rule to this translation is: $(x,y) \to (x + 5,y)$

So, we have:

$y' = (x - 5 + 5)^2 + 5$

$y' = (x - 0)^2 + 5$

Next, the resulting function is shifted down by 5 units.

The rule to this translation is: $(x,y) \to (x,y- 5)$

So, we have:

$y" = y' - 5$

This gives:

$y" = (x - 0)^2 + 5 - 5$

$y" = (x - 0)^2 + 0$

Hence, the translation from $y = (x - 5)^2 +5$ to $y = (x - 0)^2 +0$ is to shift $y = (x - 5)^2 +5$ to the left by 5 units and then downward by 5 units