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Jlenok [28]
3 years ago
11

write an equation of the graph that has a slope of -2 and a y-intercept (starting point) of 4 and graph this line

Mathematics
1 answer:
telo118 [61]3 years ago
6 0

Step-by-step explanation:

first the equation is :

y=4-2x

Now for graph :

If x=1 then y=2

(2,0) / (3,-2) / (0,4)

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(-1,-9) (8,-7) find the slope of the line through pair of points​
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the slope of line is m=2/9

Step-by-step explanation:

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Simplify -3p^3+5p+(-2p^2) +(-4) -12p +5 -(-8p^3)
GenaCL600 [577]

Simplify the following:

8 p^3 - 3 p^3 - 2 p^2 + 5 p - 12 p - 4 + 5

Grouping like terms, 8 p^3 - 3 p^3 - 2 p^2 + 5 p - 12 p - 4 + 5 = (-3 p^3 + 8 p^3) - 2 p^2 + (5 p - 12 p) + (-4 + 5):

(-3 p^3 + 8 p^3) - 2 p^2 + (5 p - 12 p) + (-4 + 5)

8 p^3 - 3 p^3 = 5 p^3:

5 p^3 - 2 p^2 + (5 p - 12 p) + (-4 + 5)

5 p - 12 p = -7 p:

5 p^3 - 2 p^2 + -7 p + (-4 + 5)

5 - 4 = 1:

Answer: 5 p^3 - 2 p^2 - 7 p + 1

7 0
3 years ago
3. Given 4x – 8y = 8:
Mazyrski [523]
Slope-intercept form is y = mx + b, so to turn that equation into slope-intercept you'll need to get y alone

4x - 8y = 8 --- subtract 4x
-8y = 8 - 4x --- divide by -8
y = -1 + (1/2)x --- reorder to match "mx + b"
y = (1/2)x - 1

in y = mx + b, "m" is the slope and "b" is the y-intercept. so for part B, your slope is (1/2) and your y-intercept is (-1). take the sign with you.

for part C, you'll need to know point-slope form: (y - y1) = m(x - x1)
you'll also need to be aware that "perpendicular" lines have a slope that is the opposite reciprocal of the original line.

the original slope is (1/2). change the sign to negative and form a reciprocal: your new slope is -2. plug that into your point-slope form

(y - y1) = m(x - x1)
(y - y1) = (-2)(x - x1)

and lastly, plug in your given point: (1, 2)

y - 2 = (-2)(x - 1)

so, just to look a little neater without all of the work:
A) y = (1/2)x - 1
B) m = (1/2), b = -1
C) y - 2 = (-2)(x - 1)
5 0
3 years ago
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