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4 years ago

Someone please help!!

Mathematics

1 answer:

dimulka [17.4K]4 years ago

7 0

Combine like terms to get

$4m^3n^3+2n+9$ !

⭐ Please consider brainliest! ⭐

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Find each value of x and y

hram777 [196]

X is 120 degrees, you ask to find the value of y, but there is no y

4 0

3 years ago

Which values of x would make a polynomial equal to zero if the factors of the polynomial were (x-5) and (x-6)

meriva

x-5= 0

move -5 to the other side

sign changes from -5 to +5

x-5+5= 0+5

x= 5

x-6= 0

x-6+6= 0+6

x= 6

Answer: B. 5 and 6

5 0

3 years ago

Read 2 more answers

Write an equation of the line that passes through point (−3, 8) and has the slope m=−2.

dangina [55]

Answer:

y=-2x+8

Step-by-step explanation:

slope formula is y=mx+b

slope(m)=-2, and y-value(b)=8

so ya just plug in what ya know to get y=-2x+8

6 0

3 years ago

Are these two correct? If not, please correct me and tell me how u figured it out.

goldfiish [28.3K]

Yes, those are correct.

6 0

4 years ago

Read 2 more answers

HELPPPP!!!! Need the answer ASAP!!

Greeley [361]

Given that the functions $f(x)=x+4$ and $g(x)=x^{3}$

We need to determine the value of the function $(g \ {\circ} f)(-3)$

First, we shall determine the composition of the function $(g \circ f)(x)$

Function $(g \circ f)(x)$ :

Let us determine the function $(g \circ f)(x)$

Thus, we have;

$(g \circ f)(x)=g[f(x)]$

$=g[x+4]$

$=(x+4)^3$

$(g \circ f)(x)=x^3+3x^2(4)+3x(4)^2+(4)^3$

$(g \circ f)(x)=x^3+12x^2+48x+64$

Thus, the function is $(g \circ f)(x)=x^3+12x^2+48x+64$

Value of the function $(g \ {\circ} f)(-3)$ :

The value of the function can be determined by substituting x = -3 in the function $(g \circ f)(x)=x^3+12x^2+48x+64$

Thus, we have;

$(g \circ f)(-3)=(-3)^3+12(-3)^2+48(-3)+64$

Simplifying the terms, we get;

$(g \circ f)(-3)=-27+12(9)+48(-3)+64$

$(g \circ f)(-3)=-27+108-144+64$

$(g \circ f)(-3)=1$

Thus, the value of the function $(g \ {\circ} f)(-3)$ is 1.

8 0

3 years ago