Question

Seung and Razi are both filling party favor bags for their birthdays at a constant rate. Razi’s progress is shown in the table.

Answer 1

Answer:

Each minute Seung fills one less bag than Razi.

Step-by-step explanation:

Find the rate of change.

Razi's rate of change:

$\dfrac{y(b)-y(a)}{b-a}\\ \\=\dfrac{y(2)-y(1)}{2-1}\\ \\=\dfrac{44-48}{2-1}\\ \\=\dfrac{-4}{1}\\ \\=-4$

Seung's rate of change:

$\dfrac{y(b)-y(a)}{b-a}\\ \\=\dfrac{y(4)-y(3)}{4-3}\\ \\=\dfrac{31-34}{4-3}\\ \\=\dfrac{-3}{1}\\ \\=-3$

This means Razi packs 4 bags per minute, Seung packs 3 bags per minute.

Difference = 4 - 3 = 1 bag

Each minute Seung fills one less bag than Razi.

Answer 2

Answer:Each minute Seung fills one less bag than Razi.

Step-by-step explanation:

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