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Svetradugi [14.3K]
3 years ago
15

Let f(x)=x^2+5 and g(x)= (x+5)/x find (g fog f)(-3)

Mathematics
1 answer:
asambeis [7]3 years ago
7 0
1+5/x
hope this helps.
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Help pleaseee! Greatly appreciated if you do
IRINA_888 [86]
36% of 24..... or 0.36 times 24= 8.64
22% of 24......or 0.22 times 24= 5.28

8.64-5.28= 3.36. D.
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3 years ago
Please help!! <br> Will mark and star!!
Kamila [148]
The answer is B. please mark me as brainlyest.
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3 years ago
60<br> What is the sum of the series E3n?
wariber [46]

Answer:

B, 2,010

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3 years ago
Read 2 more answers
The recursive rule for a sequence is an=an-1+7, where a1=15.What is the explict rule for this sequence
posledela

well, the recursive rule of aₙ = aₙ₊₁ + 7, where a₁ = 15, is simply saying that

we start of at 15, and the next term is obtained by simply adding 7, and so on.

well, that's the recursive rule.

so then let's use that common difference and first term for the explicit rule.

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\ \cline{1-1} a_1=15\\ d=7 \end{cases} \\\\\\ a_n=15+(n-1)7\implies a_n=15+7n-7\implies a_n=7n+8

5 0
3 years ago
What is the equation in vertex form of the quadratic function with a vertex at (-1, -4) that goes through (1, 8)?
cestrela7 [59]

Answer:

y = 3(x+1)^2 - 4

Step-by-step explanation:The general form of the equation of a quadratic function whose vertex is (h,k) and whose leading coefficient is a is:

y - k = a(x-h)^2, or

y      = a(x-h)^2 - k

Substituting the coefficients of the vertex (-1, -4), we get:

y      = a(x + 1)^2 - 4

Substituting the coordinates of the given point, (1,8), we get:

8      = a(1+1)^2 - 4, which simplifies to:

8      = a(2)^2 - 4, or

8  = 4a - 4.  Then 4a = 12, and a = 3.

Thus, the desired equation is y = 3(x+1)^2 - 4 (answer j).


5 0
4 years ago
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