HELP PLSSSSSSS algebra 1
1 answer:
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Answer:
(a) In attachment
(b) x = y² - 2y - 1, −2 ≤ y ≤ 4
Step-by-step explanation:
(a)
The graph of the given parametric equation is given in the attachment.
The direction in which the curve is traced as t increases, is indicated by black arrows.
(b)
To eleminate the parameter t, we simultaneously solve both the equations.
So, we have the equations:
x = t² - 2 ----- equation (1)
y = t + 1 ----- equation (2)
So, from equation (2), we have:
t = y - 1
Substituting this in equation (1), we get:
x = (y - 1)² - 2
x = y² - 2y + 1 - 2
x = y² - 2y - 1
Now, for limits of y, we use equation (2)
For initial limit, t = -3
y = - 3 + 1 = - 2
For final limit, t = 3
y = 3 + 1 = 4
Therefore, the final relation after eliminating t is:
<u>x = y² - 2y - 1, −2 ≤ y ≤ 4</u>
