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scZoUnD [109]
3 years ago
9

Find the product of 543.1187 and 100 A. 5.431187 B. 54,311.87 C. 5,431.187 D. 54.31187 Can someone also explain how they came up

with the answer so that I can understand? (do you move the decimal? If so, to the left or right? How many times you move it?
Mathematics
2 answers:
mel-nik [20]3 years ago
8 0

The answer would be 543.1187 X 100= {54311.87}

Katyanochek1 [597]3 years ago
7 0
543.1187\times100=\boxed{54311.87}

When you're multiplying by a power of 10 such as 100, the decimal point moves two places to the right. Note that this corresponds with the number of zeroes in 100. Of course our number is going to get bigger, not smaller, which means we'd have to be going right. If we multiplied by something like 0.001, we'd also be going two places, just going smaller and to the left.
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20 PoINTS!!! The line graphed below has a slope of ____. -3 -1/3 1/3 3
qwelly [4]

Answer:

-3

Step-by-step explanation:

We have two points

( -3,1)  ( -1,-5)

We can use the slope formula

m = (y2-y1)/(x2-x1)

    = ( -5-1)/(-1- -3)

    = (-5-1) / (-1+3)

    = -6/2

    = -3

5 0
3 years ago
Read 2 more answers
A student randomly guesses on 10 true/false questions. use the binomial model to determine the probability that the student gets
lana [24]

Answer:

P(5)=\frac{63}{256}

Step-by-step explanation:

we are given

A student randomly guesses on 10 true/false questions

so,

n=10

there only true and false

so, probability getting true question is

p=\frac{1}{2}

so, probability getting false question is

q=\frac{1}{2}

the student gets 5 out of 10 questions right

so,

r=5

we can use binomial probability formula

P(r)=\frac{n!}{r!(n-r)!} p^rq^{n-r}

now, we can plug values

P(5)=\frac{10!}{5!(10-5)!} (\frac{1}{2})^5(\frac{1}{2})^{10-5}

we can simplify it

and we get

P(5)=\frac{63}{256}

4 0
3 years ago
Determine whether the ordered pair (6, 1) satisfies the equation y = 10 - 4x
Viktor [21]
Plug in the point
1 = 10 - 4(6)
1 = 10 - 24
1 = -14, false
Solution: B
4 0
3 years ago
A certain forest covers an area of 2600 km2. Suppose that each year this area decreases by 7.75%. What will the area be like aft
kakasveta [241]

Answer:

After 15 years, the area will be of 775.3 km²

Step-by-step explanation:

The equation for the area of the forest after t years has the following format.

A(t) = A(0)(1-r)^{t}

In which A(0) is the initial area and r is the yearly decrease rate.

A certain forest covers an area of 2600 km2.

This means that A(0) = 2600

Suppose that each year this area decreases by 7.75%.

This means that r = 0.0775

So

A(t) = 2600(1-0.0775)^{t}

A(t) = 2600(0.9225)^{t}

What will the area be like after 15 years?

This is A(15)

A(t) = 2600(0.9225)^{t}

A(15) = 2600(0.9225)^{15} = 775.3

After 15 years, the area will be of 775.3 km²

3 0
3 years ago
Read 2 more answers
Solve the following system of linear equation by graphing. <br>4x + 2y = -2 <br>2x – 3y = 9 ​
Viefleur [7K]
If you can graph in slope intercept, your new equations would be: y= -2x-1 and y= 2/3x-3.
Just graph those now since it should be easier.
3 0
3 years ago
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