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Setler [38]
3 years ago
11

A student randomly guesses on 10 true/false questions. use the binomial model to determine the probability that the student gets

5 out of 10 questions right. Show all your steps.
Mathematics
1 answer:
lana [24]3 years ago
4 0

Answer:

P(5)=\frac{63}{256}

Step-by-step explanation:

we are given

A student randomly guesses on 10 true/false questions

so,

n=10

there only true and false

so, probability getting true question is

p=\frac{1}{2}

so, probability getting false question is

q=\frac{1}{2}

the student gets 5 out of 10 questions right

so,

r=5

we can use binomial probability formula

P(r)=\frac{n!}{r!(n-r)!} p^rq^{n-r}

now, we can plug values

P(5)=\frac{10!}{5!(10-5)!} (\frac{1}{2})^5(\frac{1}{2})^{10-5}

we can simplify it

and we get

P(5)=\frac{63}{256}

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drek231 [11]

Answer:

A

Step-by-step explanation:

y = (-2/5)x + 1

By inspection of the equation, the slope of the line is -2/5 and the y-intercept is 1.

Therefore, we can immediately discount option B and D, as their y-intercepts are NOT 1.

Find the point where the line crosses the x-axis by setting the equation to 0 and solving for x:

0 = (-2/5)x + 1

⇒ -1 = (-2/5)x

⇒ -5 = -2x

⇒ x = 5/2

Therefore, the line of the function intersects the x-axis at x = 5/2 = 2.5

From inspection of the graphs, the line in option A intersects the x-axis at 2.5.  Therefore, this is the correct graph.

3 0
2 years ago
the dog needs a 1/3 of a cup of dog food each day. the bag holds 5 cups of dog food how many days will it last ?​
sleet_krkn [62]

Answer:

15 days

Step-by-step explanation:

You have 5 cups of food, and you give him 1/3 a day.

So, <em>5 divided by 1/3</em>, which would get you 15 days. Or you could cross-multiply, meaning you multiply across, but in this case I just made them line up so you can see how to do it.(food)/(cupsperday) = 5/\frac{1}{3} \\OR\\\frac{(food)}{1}*(cupsperday) = \frac{5}{1} *\frac{3}{1}

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Did anyone get the answer??

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Alekssandra [29.7K]

Answer:

62.41

Step-by-step explanation:

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C= 3.14 x 19.875

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