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adell [148]
4 years ago
6

Wrote and solve an equation that will help you find three consecutive even numbers that sum to 600​

Mathematics
1 answer:
vladimir1956 [14]4 years ago
7 0

Answer:

198, 200 and 202

Step-by-step explanation:

Represent the three consecutive even numbers by x, x + 2, x + 4.

Then:

x + x + 2 + x + 4 = 600

Combining like terms, we get:

3x = 594, so:

x = 198

x + 2 = 200

x + 4 = 202

The three consecutive even numbers are 198, 200 and 202.

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Answer: x=2 - 1/2 x ㏒(16/2953125)

Step-by-step explanation:

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8 0
3 years ago
Please help ASAP geometry
lina2011 [118]

Answer:

A' (-6,12)

B' (9,9)

C' (-3,0)

Answered by GAUTHMATH

3 0
3 years ago
The area of a square is 102 square units. What is an
Neko [114]

Answer:

Between 10 and 11.

Step-by-step explanation:

To begin, we can look at the problem as such. If we take the first answer choice, we can find the squares of both numbers giving us: (Remember that the area of a square is A=L²)

10²= 100

11²= 121

Since the given area is in between these two numbers, this means that the side length must be between 10 and 11.

3 0
3 years ago
Read 2 more answers
Name the possible rational roots for the function using the Rational Root Theorem.
blondinia [14]

Answer:

\pm 1,\pm 3,\pm 5,\pm 15,\pm \frac{1}{3},\pm \frac{5}{3}

Step-by-step explanation:

Given:

The function is given as:

f(x)= 3x^{3}-19x^{2} +23x-15

The possible rational roots for a function f(x) = a_{n}x^{n}-a_{n-1}x^{n-1} +a_{n-2}x^{n-2}+....a_{1}x+a_{0} using the Rational Root Theorem is given as:

\pm (\frac{\textrm{Factors of }a_{0}}{\textrm{Factors of } a_{n}}})

Here, a_{0}=-15,a_{n}=3

Factors of -15 = \pm1,\pm3,\pm5,\pm15

Factors of 3 = \pm1,\pm3

Now, possible roots are given as:

\pm (\frac{\textrm{Factors of }a_{0}}{\textrm{Factors of } a_{n}}})\\\\=\pm(\frac{\pm1,\pm3,\pm5,\pm15}{\pm1,\pm3})\\\\=\pm\frac{1}{1},\pm\frac{1}{3},\pm\frac{3}{1},\pm\frac{3}{3},\pm\frac{5}{1},\pm\frac{5}{3},\pm\frac{15}{1},\pm\frac{15}{3}\\\\=\pm1,\pm\frac{1}{3},\pm3,\pm1,\pm5,\pm\frac{5}{3},\pm15,\pm5\\\\=\pm1,\pm \frac{1}{3},\pm3, \pm 5, \pm \frac{5}{3},\pm15

Therefore, option 1 is correct.

6 0
3 years ago
19. A box contains 95 pink rubber bands and 90 brown rubber bands. You select a rubber band at random from the box. Find each pr
KonstantinChe [14]
We are given with
95 pink rubber bands
90 brown rubber bands

The probability of selecting a pink rubber band is
P = 95 / (95 + 90) = 19/37
The probability of selecting a brown rubber band is
P = 90 / (95 + 90) = 18/37
8 0
3 years ago
Read 2 more answers
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