The answer I would put would be D.
Answer:
£36
Step-by-step explanation:
From the question, we are told that School allots £3000 to spend on a trip to the theatre. With regular cost of tickets of £40 each with offer for 1/5 off
Then the cost of each ticket with 1/5 off= (4/5×40)= £32
From the question, A train ticket for the day will cost £20 each.
Then total cost for each of it = £32+£20
=£52
To determine how much money that the school will have left over, If 3 teachers and the maximum number of students attend, can be expressed below by first calculating the number of students.
Let us denote the number of students as "x"
52(x+3)= < 3000
52x + 156 =< 3000
52x =< 3000 - 156
52x =< 2844
X =< 2844/52
s =< 54.69,
The max. Number of students is 54
Total number of people= Number of students + the 3 teachers
= 54+3= 57
Total cost for 57 people= (£52 × 57 people)= £2964
The amount of money the school will have as left over = (£3000 - £2964)
= £36
Answer:
For me
Step-by-step explanation:
I think it's part to whole because you are comparing holiday celebrated to total students
Let
X-----------------> number of pansies
y-----------------> number of trees
we know that
x=15*8----------> x=120 pansies
y=8 trees
cost of each trees is----------> $<span>20.75
</span>cost of each pansies is------> $2.50/6------> $5/12
[<span>expression to find Katherine’s final cost]=[cost trees]+[cost pansies]
</span>[cost trees]=y*$20.75
[cost pansies]=x*($5/12)
[expression to find Katherine’s final cost]=y*($20.75)+x*($5/12)
[expression to find Katherine’s final cost]=8*($20.75)+120*($5/12)
[expression to find Katherine’s final cost]=$166+$50
[expression to find Katherine’s final cost]=$216
the answer is
[expression to find Katherine’s final cost]=y*($20.75)+x*($5/12)
[expression to find Katherine’s final cost]=8*($20.75)+120*($5/12)
Katherine’s final cost is $216