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3 years ago

4 points

Mathematics

2 answers:

MakcuM [25]3 years ago

5 0

Answer:

16 hours

Step-by-step explanation:

In this question, we would need to find how long it will take to drive 1,200 miles.

We know that our speed is 75 mph.

In order to find your answer, we would divide 1,200 by 75 to get the time it took you to travel the whole distance.

Solve:

1,200/75 = 16

This means that it will take 16 hours to travel 1,200 miles at a rate of 75 mph.

DiKsa [7]3 years ago

5 0

Answer :

75 = 1 hour

1, 200/75 = 16 is the answer

If 75 miles per hour then use it to divide 1, 200 miles to know the hour

Hope it helped

God bless

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PLS HELP!!! factor: a. 16b^2c^12-0.25 b. 81x^6y^2-0.36a^2

mafiozo [28]

Answer:

Step-by-step explanation:

a. 16b^2c^12-0.25 can be rewritten as follows because it is the difference of two squares:

(4bc^6 - .5)(4bc^6 + .5)

b. 81x^6y^2-0.36a^2

is the difference of two squares, just like (a) (above); its factors are:

(9x^3y - 0.6a)(9x^3y + 0.6a)

7 0

3 years ago

Al bob and carl can life 240 pounds.

padilas [110]

Answer:

1020 POUNDS.

Step-by-step explanation:

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5 0

2 years ago

Please help me so much quick :)

Nadusha1986 [10]

Answer:

22 < x < 74

Step-by-step explanation:

Given 2 sides of a triangle with third side x , then

difference of 2 sides < x < sum of 2 sides , that is

48 - 26 < x < 48 + 26 , so

22 < x < 74

6 0

2 years ago

At the end of the current year, Accounts Receivable has a balance of $4,375,000; Allowance for Doubtful Accounts has a debit bal

Advocard [28]

Answer:

$226,300

Step-by-step explanation:

Given Allowance for Doubtful Accounts is estimated as $205,000 and Allowance for Doubtful Accounts has a debit balance of $21,300

#The amount of the adjusting entry for uncollectible accounts is calculated as below:

$Adjustment \ Cost=Allowance\ Doubtful\ Accounts +Doubtful \ Accounts \ Debit \ Balance\\\\=205000+21300\\\\\$226,300$

Hence, the amount of the adjusting entry for uncollectible accounts is $226,300

8 0

2 years ago

1. What is the value of the y variable in the solution to the following system of equations?

ollegr [7]

Part 1)

we have

$3x-6y=3$ ------> equation A

$7x-5y=-11$ ------> equation B

Multiply by $-7$ the equation A

$-7(3x-6y)=-7*3$

$-21x+42y=-21$ ------> equation C

Multiply by $3$ the equation B

$3*(7x-5y)=-11*3$

$21x-15y=-33$ -------> equation D

Adds equation C and equation D

$-21x+42y=-21 \\21x-15y=-33\\---------- \\ 42y-15y=-21-33\\27y=-54 \\ y=-2$

therefore

the answer Part 1) is the option A

$y=-2$

Part 2)

we have

$3x+y=6$

$y=-3x+6$ ------> equation A

$6x+2y=8$

Simplify Divide by $2$ both sides

$3x+y=4$

$y=-3x+4$ ------> equation B

the lines A and B are parallel lines, because the slope m is equal

The system has no solution

therefore

the answer Part 2) is the option D

There is no x value as there is no solution to the system.

Part 3)

we have

$4x+2y=6$ ------> equation A

$x-y=3$

$y=x-3$ ------> equation B

substitute equation B in equation A

$4x+2[x-3]=6$

$6x-6=6$

$6x=12$

$x=2$

therefore

the answer part 3) is the option D

$x=2$

Part 4)

Let

x---------> The number of one-step equations

y---------> The number of two-step equations

we know that

$x+y=1,120$

$x=1,120-y$ -------> equation A

$3x-2y=1,300$ ------> equation B

substitute equation A in equation B

$3[1,120-y]-2y=1,300$

$3,360-5y=1,300$

$5y=3,360-1,300$

$5y=2,060$

$y=412$

therefore

the answer part 4) is the option D

$y=412$

8 0

3 years ago

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