Given a polynomial
and a point
, we have that

We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of

Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be

To fix the correct value for a, we impose
:

And so we must impose

So, the function we're looking for is

Hey there, Dudedan!
In a#b = a+2b, we have the first term, a, plus 2 times the second term, b.
Let's try that with 3#4.
3#4 = 3+2(4) =
3 + 8 = 11.
Hope this helps!
Answer:
A
Step-by-step explanation:

Expand parentheses:

Move all y's to one side and numbers to the other:

Divide both sides by -6. Since you are dividing both sides by a negative number, you need to flip the comparator:

Hope this helps!
Answer:d i believe
Step-by-step explanation:
if im wrong i will get hate comments, im already hated by everyone so it dont matter