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enot [183]
3 years ago
7

I need some help please I’d really appreciate it this is due in 25 mins.

Mathematics
2 answers:
Pani-rosa [81]3 years ago
6 0

Answer:

2 years

Step-by-step explanation:

LekaFEV [45]3 years ago
4 0

Answer:

i dont think that it much easier may be 2years

Step-by-step explanation:

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Graph f(x) = 6x^2-11+3 and<br> find the zeroes
babunello [35]

Answer:

x = ±1.155

Step-by-step explanation:

We need to graph the given function f(x) = 6x^2-11+3 and find its zeroes.

The attached figure shows the graph of the given function.

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Put f(x) = 0

So,

6x^2-11+3=0\\\\x=\pm 1.155

Hence, this is the required solution.

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3 years ago
In ΔJKL, solve for x. (4 points) Triangle JKL where angle K is a right angle. KL measures 34. JL measures x. Angle J measures 27
zhannawk [14.2K]

Answer:

74.8

Step-by-step explanation:

The triangle in question is a right angled triangle since one of the angles given is a right angle (90°)

KL is the base of the triangle which serves as the opposite of the triangle since it is facing the opposite side of the angle J.

Given angel J = 27°

If KL = 34

JL will be the hypotenuse which is the longest side of the triangle = x

Using the trigonometry identities, SOH CAH TOA

Sin(theta) = Opposite/Hypotenuse

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Opposite = 34

Sin27° = 34/Hypotenuse

Hypotenuse = 34/sin27°

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3 years ago
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