Answer:
Step-by-step explanation:
The given expression: ![4 \sqrt[5]{x^{3}} \cdot y^{4} \cdot \sqrt{x} \cdot \sqrt[3]{y^{5}}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%20%5Ccdot%20y%5E%7B4%7D%20%5Ccdot%20%5Csqrt%7Bx%7D%20%5Ccdot%20%5Csqrt%5B3%5D%7By%5E%7B5%7D%7D)
Step 1: Change radical to fractional exponent.
Formula for fractional exponent: ![\sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
The power to which the base is raised becomes the numerator and the root becomes the denominator.
Step 2: Apply law of exponent for a product 
Multiply powers with same base.
Take LCM for the fractions in the power.
Hence the simplified form of ![4 \sqrt[5]{x^{3}} \cdot y^{4} \cdot \sqrt{x} \cdot \sqrt[3]{y^{5}} \text { is } 4 x^{\frac{11}{10}} \cdot y^{\frac{17}{3}}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D%20%5Ccdot%20y%5E%7B4%7D%20%5Ccdot%20%5Csqrt%7Bx%7D%20%5Ccdot%20%5Csqrt%5B3%5D%7By%5E%7B5%7D%7D%20%5Ctext%20%7B%20is%20%7D%204%20x%5E%7B%5Cfrac%7B11%7D%7B10%7D%7D%20%5Ccdot%20y%5E%7B%5Cfrac%7B17%7D%7B3%7D%7D)
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Answer: 7.33980582 x 10^0
Step-by-step explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. The sign of the exponent will depend on the direction you are moving the decimal.
H(t)=-16t²+500
0=-16t²+500
16t²=500
t²=31.25
t=5.9 seconds before the object hits the ground
☺☺☺☺
Answer:
The statement is true that a function is a relation in which each y value has ONLY 1 x value.
Step-by-step explanation:
The statement is true that a function is a relation in which each y value has ONLY 1 x value.
The reason is very clear that we can not have the repeated x-values (two same x-values).
For example, given the set of the ordered pairs of a relation
{(3, a), (6, b), (6, c)}
As the same x values (x=6) has two different Y values. Hence, the stated relation is not a function.
In order to be a function, a relation must have only 1 x-value for each y-value.
Therefore, the statement is true that a function is a relation in which each y value has ONLY 1 x value.
That's definitely an example of exponential decay, since the base (1/2) (also called the "common ratio") is greater than 0 but less than 1.
