X=- 4/5
X=-0.8
That’s the answer to your problem to your question
Answer:
3,400,000
Step-by-step explanation:
refer to attached for reference
in our case, the digit in the hundred thousands place is the number 4.
How we round this digit depends on the digit directly to the right of it (i.e the ten-thousands place).
If the digit to the right is less than 5, then leave the digit in the hundred thousands place the same and make everything else to the right zeros.
if the digit to the right is 5 or greater, then increase the digit in the hundred thousands place by 1 and then make everything else to the right zeros.
in our case, the digit to the right of the hundred thousands place is the number 2, this is less than 5, so we leave 4 the same and make everything esle to the right zero.
i.e. 3,400,000
The answers would be 3, 3, 4, 4, 5, 5. those are the answers. I don't know if that is what you wanted me to answer or not.
Answer:
3xy² - 14y²
Step-by-step explanation:
I hope that this is the problem
- x²y + [ - (x²y - 2xy² + y²) + (xy² - 3y² + x²y)] - (10y² - x²y)
= - x²y + [ - x²y + 2xy² - y² + xy² - 3y² + x²y] - 10y² + x²y
Now combine like terms in the [ ].
= - x²y + [ -x²y + x²y + 2xy² + xy² - y² - 3y² ] - 10y² + x²y
= - x²y + [ 0 + 3xy² - 4y²] - 10y² + x²y
= - x²y + 3xy² - 4y² -10y² + x²y Now combine like terms
= (-x²y + x²y) + 3xy² + (-4y² - 10y²)
= 0 + 3xy² - 14y²
= 3xy² - 14y² or y²(3x - 14)
![\huge \bf༆ Answer ༄](https://tex.z-dn.net/?f=%5Chuge%20%5Cbf%E0%BC%86%20Answer%20%E0%BC%84)
Let's solve ~
![\qquad \looparrowright \sf - 7 \sqrt{80 {x}^{4} y {}^{2} }](https://tex.z-dn.net/?f=%5Cqquad%20%5Clooparrowright%20%5Csf%20-%207%20%5Csqrt%7B80%20%7Bx%7D%5E%7B4%7D%20y%20%7B%7D%5E%7B2%7D%20%7D%20)
![\qquad \looparrowright \sf - 7 \sqrt{2 {}^{4} \times 5 \times {x}^{4} \times {y}^{2} }](https://tex.z-dn.net/?f=%5Cqquad%20%5Clooparrowright%20%5Csf%20-%207%20%5Csqrt%7B2%20%7B%7D%5E%7B4%7D%20%20%5Ctimes%205%20%5Ctimes%20%20%7Bx%7D%5E%7B4%7D%20%20%5Ctimes%20%20%7By%7D%5E%7B2%7D%20%7D%20)
![\qquad \looparrowright \sf - 7 \times {2}^{2} \times {x}^{2} \times y \times \sqrt{5}](https://tex.z-dn.net/?f=%5Cqquad%20%5Clooparrowright%20%5Csf%20-%207%20%5Ctimes%20%20%7B2%7D%5E%7B2%7D%20%20%5Ctimes%20%20%7Bx%7D%5E%7B2%7D%20%20%5Ctimes%20y%20%5Ctimes%20%20%5Csqrt%7B5%7D%20)
![\qquad \looparrowright \sf - 28 {x}^{2} y \sqrt{5}](https://tex.z-dn.net/?f=%5Cqquad%20%5Clooparrowright%20%5Csf%20-%2028%20%7Bx%7D%5E%7B2%7D%20y%20%5Csqrt%7B5%7D%20)
Therefore, Option D is correct ~