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3 years ago

PLZ HELP ME W DIS ASAP!!! MARKING BRAINIEST!!!

Mathematics

1 answer:

zepelin [54]3 years ago

7 0

Answer:

x = ±11

Step-by-step explanation:

x^2 = 121

Take the square root of each side

sqrt(x^2) = ±sqrt(121)

x = ±11

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A typical human stomach can hold up to 4 cups of food. Write an inequality to represent how many cups of food a stomach can hold

Ede4ka [16]

5cups \= 4 cups

5 represents the amount of food held in the stomach and 4 represents the amount of food that can be held in the stomach

7 0

3 years ago

If anyone knows please help me

pishuonlain [190]

Answer:

Step-by-step explanation:

Standard form of a circle is given by,

(x - a)² + (y - b)² = r²

Here, (a, b) is the center and 'r' is the radius of the circle.

For a circle having center (8, -4) and radius r = 1

Equation of the circle will be,

(x - 8)² + (y + 4)² = 1²

(x - 8)² + (y + 4)² = 1

Option (1) is the answer.

Question (2)

Circle with the center (-1, 0) and a point (2, -4) on it,

Radius of the circle = Distance between the center and the given point on circumference

= $\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

= $\sqrt{(-1-2)^2+(0+4)^2}$

= $\sqrt{9+16}$

= 5

Therefore, equation of the circle will be,

(x + 1)² + (y - 0)² = 5²

(x + 1)² + y² = 25

8 0

3 years ago

(3t^2+1)-t^2. How do you do this equation and what’s the answer. Algebra 1.

Oksana_A [137]

2t^2+1

Subtract t^2 from 3t^2 you get 2t^2

which is 2t^2+1 answer

3 0

3 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

A group of 2n people, consisting of n men and n women, are to be independently distributed among m rooms. Each woman chooses roo

vfiekz [6]

Step-by-step explanation:

Assume that

$X_i = \left \{ {{1, If , Ith, room, has,exactly, 1,man, and , 1,woman } \atop {0, othewise} \right.$

hence,

$x = x_1 + x_2+....+x_m$

now,

$E(x) = E(x_1+x_2+---+x_m)\\\\E(x)=E(x_1)+E(x_2)+---+E(x_m)$

attached below is the complete solution

7 0

3 years ago