An 8th-degree polynomial needs 9 terms that involve
x⁸, x⁷, ..., x¹, and x⁰.
x=10 implies that (x-10) is a factor of the polynomial according to the Remainder theorem.
Let the polynomial be of the form
f(x) = a₁x⁸ + a₂x⁷ + a₃x⁶ +a₄x⁵ + a₅x⁴ + a₆x³ + a₇x² + a₈x + a₉
The first few lines of the synthetic division are
10 | a₁ a₂ a₃ a₄ a₅ a₆ a₇ a₈ a₉ ( the first row has 9 coefficients)
-----------------------------------------
a₁
Answer:
The first row has 9 coefficients.
The answer here is C. Let's proof.
Since we are dealing with whole numbers, select a constant for x to satisfy that y will result a whole number.
If x = 1, then the function would be 1 + 4y = 9. Solving for y,
4y = 9 - 1
4y = 8
y = 2
In ordered pair, that is (1,2)
Next, if x = 5, then 5 + 4y = 9. Solving for y,
4y = 9 - 5
4y = 4
y = 1
In ordered pair, that is (5,1).
Lastly, if x = 9, then 9 + 4y = 9. Solving for y,
4y = 9 - 9
y = 0/4
y = 0
In order pair, that is (9,0).
-10+2b+8
-2+8b+8
Calculated sum
-2+8b
Answer is -2+8b
Answer:
54
Step-by-step explanation:
162/3 = 54
