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Lyrx [107]
3 years ago
15

Which is the graph of a quadratic equation that has a negative discriminant?

Mathematics
2 answers:
Andre45 [30]3 years ago
7 0

Answer:

The correct graph is D.

Step-by-step explanation:

Given a quadratic equation :

y=ax^{2}+bx+c

You can find the roots (where the graph intersects the x-axis) applying the following equation :

x1=\frac{-b+\sqrt{b^{2}-4ac}}{2a}

and

x2=\frac{-b-\sqrt{b^{2}-4ac}}{2a}

We define the discriminant as b^{2}-4ac

If b^{2}-4ac>0 then the graph will intersect the x-axis in two points

If b^{2}-4ac=0 then the graph will intersect the x-axis in one point.

Finally, If b^{2}-4ac then the graph won't intersect the x-axis because it will not have real roots.

In this exercise, the graph that doesn't intersect the x-axis is graph D.

Natasha2012 [34]3 years ago
5 0

Answer:

D

Step-by-step explanation:

A negative discriminant indicates that the quadratic equation has no real roots.

Thus the graph does not touch or intersect the x- axis

The only graph that does not touch or intersect the x- axis is the fourth one

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Find the vertex, focus, directrix, and focal width of the parabola.
ANEK [815]

Answer:

Vertex: (0, 0); Focus: (0, -4); Directrix: y = 4; Focal width: 16 ⇒ answer (a)

Step-by-step explanation:

* Lets revise some facts about the parabola

- Standard form equation for a parabola of vertex at (0 , 0)

- If the equation is in the form  x² =  4py, then  

- The axis of symmetry is the y-axis,  x = 0  

- 4p  equal to the coefficient of y in the given equation to

  solve for  p

- If  p  >  0, the parabola opens up.

- If  p <  0, the parabola opens down.

- Use  p  to find the coordinates of the focus,  (0  ,  p)

- Use  p  to find equation of the directri ,   y= − p

- Use  p  to find the endpoints of the focal diameter,  (±2p  ,  p)

* Now lets solve the problem

- The vertex of the parabola is (0 , 0)

∵ -1/16x² = y ⇒ multiply each side by -16

∴ x² = -16y

∴ 4p = -16 ⇒ ÷ 4 tbe both sides

∴ p = -4

∵ The focus is (0 , p)

∴ The focus is (0 , -4)

∵ The directrix is y = -p

∴ The directrix is y = -(-4) = 4 ⇒ y = 4

∵ The endpoints of the focal diameter,  (±2p  ,  p)

∴ The focal width = 2p - (-2p) = 4p

∴ The focal width = 4 ×  I-4I = 16

* Vertex: (0, 0); Focus: (0, -4); Directrix: y = 4; Focal width: 16

6 0
3 years ago
Read 2 more answers
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