The slope intercept form for y=x-2

I dont understand this

Westkost [7]

Answer:

$\dfrac{1}{2x(x-1)}$

Step-by-step explanation:

Given

$\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)$

Consider the numerator:

$x^2+2x+1=(x+1)^2$

Consider the denominator:

$x^2-1=(x-1)(x+1)$

Hence, the fraction becomes

$\dfrac{(x+1)^2}{(x-1)(x+1)}=\dfrac{x+1}{x-1}$

Consider the expression in brackets:

$2x^2+2x=2x(x+1)$

Divide:

$\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)=\dfrac{x+1}{x-1}\div 2x(x+1)=\dfrac{x+1}{x-1}\times \dfrac{1}{2x(x+1)}=\dfrac{1}{2x(x-1)}$

4 0

3 years ago

The Oregon Department of Health web site provides information on the cost-to-charge ratio (the percentage of billed charges that

Alekssandra [29.7K]

Answer:

We conclude that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care.

Step-by-step explanation:W

We are given with the cost-to-charge ratios for both inpatient and outpatient care in 2002 for a sample of six hospitals in Oregon below;

Hospital 2002 Inpatient Ratio 2002 Outpatient Ratio

1 68 54

2 100 75

3 71 53

4 74 56

5 100 74

6 83 71

Let $\mu_1$ = mean cost-to-charge ratio for outpatient care

$\mu_2$ = mean cost-to-charge ratio for impatient care.

SO, Null Hypothesis, $H_0$ : $\mu_1 \geq \mu_2$ {means that the mean cost-to-charge ratio for Oregon hospitals is higher or equal for outpatient care than for inpatient care}

Alternate Hypothesis, $H_A$ : $\mu_1 < \mu_2$ {means that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care}

The test statistics that would be used here is Two-sample t-test statistics because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n__1_+_n_2_-_2$

where, $\bar X_1$ = sample mean cost-to-charge Outpatient Ratio = $\frac{\sum X_1}{n_1}$ = 63.83

$\bar X_2$ = sample mean cost-to-charge Impatient Ratio = $\frac{\sum X_2}{n_2}$ = 82.67

$s_1$ = sample standard deviation for Outpatient Ratio = $\sqrt{\frac{\sum (X_1-\bar X_1 )^{2} }{n_1-1} }$ = 10.53

$s_2$ = sample standard deviation for Impatient Ratio = $\sqrt{\frac{\sum (X_2-\bar X_2 )^{2} }{n_2-1} }$ = 14.33

$n_1$ = sample of hospital for outpatient care = 6

$n_2$ = sample of hospital for outpatient care = 6

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(6-1)\times 10.53^{2}+(6-1)\times 14.33^{2} }{6+6-2} }$ = 12.574

So, the test statistics = $\frac{(63.83-82.67)-(0)}{12.574 \times \sqrt{\frac{1}{6}+\frac{1}{6} } }$ ~ $t_1_0$

= -2.595

The value of t test statistics is -2.595.

Now, at 5% significance level, the t table gives critical value of -1.812 at 10 degree of freedom for left-tailed test.

Since, our test statistics is less than the critical value of t as -2.595 < -1.812, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care.

8 0

3 years ago

HELP AND EXPLAIN

omeli [17]

The relative frequency of 15/24 for this considered situation represents the situation given by: Option C: Out of all the family members that prefer a lake, 15 are children.

<h3>How to find the relative frequency?</h3>

Relative frequency is the ratio of the considered sub group's count to the total count. (so its frequency of the considered sub group relative to the total frequency). (subgroup being group defined by a row, or a column)

<h3>How to form two-way table?</h3>

Suppose two dimensions are there, viz X and Y. Some values of X are there as $X_1, X_2, ... , X_n$ and some values of Y are there as $Y_1, Y_2, ... , Y_n$

List them in title of the rows and left to the columns. There will be $n \times k$ table of values will be formed(excluding titles and totals), such that:

Value(ith row, jth column) = Frequency for intersection of $X_i$ and $Y_j$ (assuming X values are going in rows, and Y values are listed in columns).

Then totals for rows, columns, and whole table are written on bottom and right margin of the final table.

For n = 2, and k = 2, the table would look like:

$\begin{array}{cccc}&Y_1&Y_2&\rm Total\\X_1&n(X_1 \cap Y_1)&n(X_1\cap Y_2)&n(X_1)\\X_2&n(X_2 \cap Y_1)&n(X_2 \cap Y_2)&n(X_2)\\\rm Total & n(Y_1) & n(Y_2) & S \end{array}$

where S denotes total of totals, also called total frequency.

n is showing the frequency of the bracketed quantity, and intersection sign in between is showing occurrence of both the categories together.

The given two-way frequency table is:

Lake Hike Total

Children 6

Adults 9

Total 14 38

Total of hike subgroup is 14, out of which children are 6, so adults going for hiking must be 14 - 6 = 8 as adults and children going for hiking together are 14 in counts.

So, we get:
n(Hike ∩ Children) = 8

Thus, the total of subgroup Adults is 9+8=17 = n(Adults)

Total of vertical total columns is: n(Children) + n(Adults) = 38

or, we get: n(Children) = 38 - 17= 21

Since total of children subgroup is:

n(Lake ∩ Children) + n(Hike ∩ Children) = n(Children)

Thus, we get:
n(Lake ∩ Children) + 6 = 21

n(Lake ∩ Children) = 21-6 = 15

Thus, sum of the 'lake' subgroup is:

n(Lake) = n( Lake ∩ Children) + n(Lake ∩ Adults)

n(Lake) = 15 + 9 = 24

Thus, the completed two-way table is:

Lake Hike Total

Children 15 6 21

Adults 9 8 17

Total 24 14 38

Now, we've to find what does 15/24 represents.

The division is done by 24, which is the total of "lake" subgroup.

And in that lake subgroup, we have:

n(Lake ∩ Children) = 15

Thus, 15/24 is the relative frequency of those children who prefer the lake, relative to total number of people who prefer lake.

Thus, the relative frequency of 15/24 for this considered situation represents the situation given by: Option C: Out of all the family members that prefer a lake, 15 are children.

Learn more about conditional relative frequency here:

brainly.com/question/8358304

Learn more about two-way table here:

brainly.com/question/26788374

#SPJ1

3 0

2 years ago

4. Algebra If in one year a city

vredina [299]

Answer:

268.25

Step-by-step explanation:

by using the fact that one year is 365.25 days, we can subtract our 365.25 by our 97 to get 268.25, written in the equation of 365.25-97=268.25

*edit, messed up how long a year was, corrected my issue, answer & equation.

7 0

3 years ago

Can someone pls help me rn

Butoxors [25]

Domain (7,5,7) domain is the x value
range(-8,8,6) range is the y value

hope this helped

5 0

3 years ago

The slope intercept form for y=x-2​

The slope intercept form for y=x-2