All categories

3 years ago

Help me please help

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

7 0

That would be A :D It would be A because you would do keep change flip. You would keep 5/6, change the division sign to multiplication, then flip the 5/16 to 16/5 (the reciprocal)

You might be interested in

a family has five children The probability of having a gil is 1/2 What is the probability of having exactly 2 girls out of five

My name is Ann [436]

P(no girls in five births) = p(five boys) = (1/2)^5 = 1/32 = 0.0313

4 0

4 years ago

What is the GCF of h4 and h8

Naily [24]

The greatest common factor is to h4 and h8 is 4

7 0

3 years ago

Shauna makes 24 cupcakes per hour. She has already made 48 cupcakes. Let x represent the amount of time Shauna spends making the

GalinKa [24]

Y=24x+48

24 per hour (x) plus the 48 she already made would equal a total (y).

3 0

3 years ago

What are the powers of 4 through 1000

Ahat [919]

Answer:

{4^0, 4^1, 4^2, 4^3, 4^4}, or, with a bit of rounding off,

{4^0, 4^1, 4^2, 4^3, 4^4, 4^5} = {1, 4, 16, 64, 256, 1024}

Step-by-step explanation:

I wanted to determine the largest power of 4 that does not exceed 1000. Here's what I did:

4^x = 1000. Taking the ln of both sides, we get x ln 4 = ln 1000.

6.9078

Solving for x: x = --------------- = 4.98

1.3863

Thus, the answer to this question is {4^0, 4^1, 4^2, 4^3, 4^4}. If you're willing to talk in terms of approximations, then there'd be one more power of 4 in this set: 4^5. Note that 4^5 = 1024, whidh is just a bit over 1000.

7 0

3 years ago

About 1/4 of all adults in the United States have type O+ blood. If three randomly selected adults donate blood, find the probab

valina [46]

Answer:

a) 0.0156

b) 0.4219

c) 0.1406

Step-by-step explanation:

We are given the following information:

We treat adult having type O+ blood as a success.

P(Adult have type O+ blood) = 0.25

Then the number of adults follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 3

a) All three are type O+

$P(x =3)\\= \binom{3}{3}(0.25)^3(1-0.25)^0\\= 0.0156$

b) None of them is type O+

$P(x =0)\\= \binom{3}{0}(0.25)^0(1-0.25)^3\\= 0.4219$

c) Two out of the three are type O

$P(x =2)\\= \binom{3}{2}(0.25)^2(1-0.25)^1\\= 0.1406$

6 0

3 years ago

Help me please help ​

Help me please help