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Anna35 [415]
3 years ago
11

Click on all that are true about the graph of y > x^2 + 4x + 4.

Mathematics
2 answers:
Kryger [21]3 years ago
7 0

Answer:

The correct options are:

a) The parabola opens up.

c) The vertex is at (-2,0).

d) The parabola is dashed.

Step-by-step explanation:

We are given an algebraic inequality as:

y > x^2 + 4x + 4:

This implies that:

y> (x+2)^2

The options that holds true regarding this inequality is:

a)

The parabola opens up.

Since the coefficient of the leading term is positive.

c)

The vertex is at (-2,0).

d)

The parabola is dashed.

Since the inequality is a strict inequality.

( The line of symmetry of parabola is x=-2.

Also the parabola is shaded inside )

vladimir1956 [14]3 years ago
5 0
the answer is a,b,d
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NO ONE EVER ANSWERS MY QUESTIONS I NEED HELP PLEASE!!! 2 problems Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM. a
almond37 [142]

To solve this problem we will use sinus theorem.

It's general form is

a/sinα = b/sinβ = c/sinγ  

In this case it reads ML/sin∡K = KL/sin∡M = KM/sin∡L  =>

ML/sin∡K = KL/sin∡M  =>  12/sin60° = KL/sin45° => 12/(√3/2) = KL/(√2/2) =>

2*12/√3 = 2*KL/√2 => We will divide whole equation with number 2 and get

12/√3=KL/√2 => KL*√3=12√2 => KL=(12√2)/√3

When we rationalize denominator we get  KL=4√6≈ 4*2.45= 9.8

Considering that we know two angles we will calculate the third

∡K+∡M+∡L=180° => 60°+45°+∡L=180° => ∡L= 180-105=75°

Reason- The theorem of the sum of the inner angles of the triangle

ML/sin∡K=KM/sin∡L => 12/sin60°=KM/sin75°

We will calculate  sin75° = sin (30+45)= sin30 *cos45+cos30*sin45 =>

sin75°= 1/2 * √2/2 = √3/2 * √2/2= √2/4 *(√3+1)≈(1.41/4)*(1.73+1)=0.96

12/(√3/2)=KM/0.96 => 12*2/√3=KM/0.96 => 13.87=KM/0.96 =>

KM=13.87*0.96= 13.31

Perimeter of ΔKLM => P=KL+ML+KM= 12+9.8+13.31= 35.11

In the same way you can calculate perimeter of ΔMNO.

Good luck!!!


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