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P(A) =0.54
P(B)= 0.68
P'(A)= 1-0.54 = 0.46
P'(B)= 1- 0.68 = 0.32
The probability of neither of both event will occur:
= P'(A)×P'(B)
=0.46 × 0.32
=0.1472
Answer:
25.15 ponds is the weight of two year old baby corresponds to 10th percentile.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 29 pounds
Standard Deviation, σ = 3 pounds
We are given that the distribution of weight of two year old babies is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.10
P(X < x)
Calculation the value from standard normal z table, we have,

Thus, 25.15 ponds is the weight of two year old baby corresponds to 10th percentile.
Answer: y+6x = -34
<em><u>Step-by-step explanation:</u></em>
y-2= -6(x+6) (<u><em>Ax+By=C is the goal)</em></u>
y-2= -6x-36 <u>(-6) x & (-6) 6</u>
y=-6x-34 (Add 2 to both sides)
<em>y+6x = -34 [Add 6x to both sides]</em>