All categories

3 years ago

Y+3=-2(x+1) find the slope and point on the line?

Mathematics

2 answers:

ad-work [718]3 years ago

7 0

The slope is -2
a point on the line is (0, -5)

professor190 [17]3 years ago

6 0

Answer:

m= -2

y intercept: (0.-5)

Step-by-step explanation:

hope this helps

You might be interested in

Population of fruit flies has a mean life span of 46 days with a standard deviation of 6.2 days. If a sample of 30 fruit flies i

icang [17]

Idk sorry I would answer if I did but I need points to ask a question

7 0

3 years ago

What information do you get from a bar graph

Step2247 [10]

Numbers shade ins and lines

7 0

2 years ago

Read 2 more answers

How would logx (49) = x look like in exponential form

Ivanshal [37]

I'm assuming the given log equation is $\log_{\text{x}}(49) = \text{x}$

If so, then the exponential form is $\text{x}^{\text{x}} = 49$

This is because the general form $\log_{\text{b}}(\text{x}) = \text{y}$ transforms into $\text{y} = \text{b}^{\text{x}}$

For both equations, the 'b' is the base.

5 0

1 year ago

Newberg is 5 miles due north of the airport, and Rockport is 12 miles due east of the airport. How far apart are Newberg and Roc

amid [387]

Step-by-step explanation:

No of miles Newberg is north of airport = 5

No of miles Rockport is east of the airport = 12

No of miles Newberg and Rockport are apart = 12+5 =17

8 0

3 years ago

An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let

Advocard [28]

Answer:

$P(t)=3,000,000-3,000,000e^{0.0138t}$

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

$P'(t)=K(3,000,000-P(t))$

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

We have and ordinary differential equation of first order that we can write

$P'(t)+KP(t)= 3,000,000K$

The <em>integrating factor </em>is

$e^{Kt}$

Multiplying both sides of the equation by the integrating factor

$e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K$

Hence

$(e^{Kt}P(t))'=3,000,000Ke^{Kt}$

Integrating both sides

$e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C$

$e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C$

$P(t)=3,000,000+Ce^{-Kt}$

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

$e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138$

And the equation that models the number of people (in millions) who become aware of the product by time t is

$P(t)=3,000,000-3,000,000e^{0.0138t}$

5 0

3 years ago