WILL GIVE BRAINLIEST: Show that ABCD is a rhombus if A(0, –2), B(10, 3), C(21, 5), and D(11, 0). Find the slope m1 of AC and the
slope m2 of BD and verify that m1m2 = –1.
1 answer:
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Both refer to the inverse sine function.
The inverse sine (or arcsine) of x:
where x is a real number in the domain of the function:
and the arcsine function returns an angle in the interval![\mathsf{\left[-\,\frac{\pi}{2},\,\frac{\pi}{2}\right]:}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cleft%5B-%5C%2C%5Cfrac%7B%5Cpi%7D%7B2%7D%2C%5C%2C%5Cfrac%7B%5Cpi%7D%7B2%7D%5Cright%5D%3A%7D)
So if you see anywhere one of these expressions below
then you should look for an angle
that satisfies the following conditions:
This angle is called the inverse sine of the real number x.
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Pay attention and do not mistake the arcsine function for the reciprocal of sine (which is cosecant); especially if you prefer or see that notation with an superscript -1. This one can be easily mistaken for an exponent:
but the reciprocal is something like
![\mathsf{\big[sin(x)\big]^{-1}=\dfrac{1}{sin\,(x)}=csc(x)\qquad\quad(!!)}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cbig%5Bsin%28x%29%5Cbig%5D%5E%7B-1%7D%3D%5Cdfrac%7B1%7D%7Bsin%5C%2C%28x%29%7D%3Dcsc%28x%29%5Cqquad%5Cquad%28%21%21%29%7D)
and this last one has a total different meaning.
I hope this helps. =)
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Both refer to the inverse sine function.
The inverse sine (or arcsine) of x:
where x is a real number in the domain of the function:
and the arcsine function returns an angle in the interval
So if you see anywhere one of these expressions below
then you should look for an angle
This angle
______
Pay attention and do not mistake the arcsine function for the reciprocal of sine (which is cosecant); especially if you prefer or see that notation with an superscript -1. This one can be easily mistaken for an exponent:
but the reciprocal is something like
and this last one has a total different meaning.
I hope this helps. =)
Answer:
The sum of the squares of the two sides equals the square of the hypotenuse (a² + b² = c²).
Let's say you have a triangle with a 90º angle (also known as a right angle). The two equal legs are a and b while the hypotenuse is the longer side. Hypotenuse is and always will be c.
Here's a problem:
c ⊿ a (12)
b (6)
C is missing, we have to find C, so here's what we do:
Step 1: You square all the numbers in the equation
12² + 6² = c²
↓
144 + 36 = c
Step 2: You add 144 + 36 and you get 180
Step 3: Then you find the square root >> and you get ≈13.4
Now sometimes, the a or b would be missing, for example:
c (13)⊿ a
b (5)
A is missing (when a or b is missing, use the following formula, do not use the same formula when c is missing)
Step 1: You square all the numbers in the equation
a² + 5² = 13²
a + 25 = 169
For this next part, you must subtract a or b (in this case, b) on both sides, for example:
25 – 25 = 169 - 25
25 – 25 cancels itself out so now we subtract 169 by 25 and we get 144.
Then we find the square root of 144 and we get 12
I hope this helps :)
Answer:
9
Step-by-step explanation:
hello
hope this helps