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lorasvet [3.4K]
1 year ago
7

christy uses glass beads to make braclets and necklances it takes her 30 minutes to make a bracelet and 45 minites to make a nec

klace she works at.most 40 hours she wants to make atleast 30 bracelts the profit from the bracelets os $10 and the profit from a necklace is 18 determine make to maximize her.profit show your work compare the solution of a system of linear inequalities and the solution to an equation calculated by linear program
Mathematics
1 answer:
shtirl [24]1 year ago
4 0

Christy should make at least 30 bracelets and at most 40 necklaces to maximize profit

<h3>How to determine how many bead of each type of bracelets and necklaces should Christy make to maximize his​ profit?</h3>

The given parameters can be represented in the following tabular form:

                       Bracelet (x)    Necklace (y)    Total              

Labor (hour)        0.5                       0.75         40

Profit                    10                         18

From the above table, we have the following:

Objective function:

Max P = 10x + 18y

Subject to:

0.5x + 0.75y <= 40

Because she wants to make at least 30 bracelets, we have:

x >= 30

So, we have:

Max P = 10x + 18y

Subject to:

0.5x + 0.75y <= 40

x >= 30

Express x >= 30 as equation

x = 30

Substitute x = 30 in 0.5x + 0.75y <= 40

0.5 * 30 + 0.75y <= 40

This gives

15 + 0.75y <= 40

Subtract 15 from both sides

0.75y <= 30

Divide by 0.75

y <= 40

Hence, Christy should make at least 30 bracelets and at most 40 necklaces to maximize profit

Read more about maximizing profits at:

brainly.com/question/13799721

#SPJ1

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What is the quotient (125 – 8x3) ÷ (25 + 10x + 4x2)? –2x + 5 2x – 5 –2x – 5 2x + 5
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ANSWER

\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = - 2x+5

EXPLANATION

We have been given the quotient,

\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} }
to simplify.

We need to rewrite the numerator as difference of two cubes.

\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ {5}^{3} - ( {2x})^{3} }{ 25 + 10x + 4 {x}^{2} }

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Then the numerator becomes,

\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ (5 - 2x)(25 + 5 (2x) + {(2x)}^{2}) }{ 25 + 10x + 4 {x}^{2} }

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\frac{125 - 8 {x}^{3} }{ 25 + 10x + 4 {x}^{2} } = \frac{ (5 - 2x)(25 + 10x + 4 {x}^{2}) }{ 25 + 10x + 4 {x}^{2} }

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Answer:

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