Answer:
.055
Step-by-step explanation:
Answer:
0.1056 = 10.56% probability that the concentration exceeds 0.60
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that the concentration exceeds 0.60?
This is 1 subtracted by the pvalue of Z when X = 0.6. So



has a pvalue of 0.8944
1 - 0.8944 = 0.1056
0.1056 = 10.56% probability that the concentration exceeds 0.60
The two ways to decompose 6107
1+6106
2+6105
Answer:
Estimate of the standard error of the mean = 0.38 lb
Step-by-step explanation:
We are given the following in the question:
Sample mean,
= 10.87 lb
Sample size, n = 131
Standard deviation, σ = 4.31 lb
We have ti find the estimate of the standard error of the mean.
Formula for standard error:

Putting values, we get,

0.38 lb is the standard error of the mean.
3/10
Calm down u got this;)