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Tom [10]
3 years ago
5

HELP MEEEE PLEASE ;C

Mathematics
2 answers:
Nata [24]3 years ago
7 0
I got y= 3x because from the origin you go up three and over one, and the y- intercept in 0 so I don’t think you put anything there
Setler79 [48]3 years ago
3 0
I think the answer is y=3x
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A toll-free sales line sold 85 products for every 125 calls in one day. What is the daily success rate of the sales line? A. 0.1
IgorLugansk [536]

Answer:

C. 0.68

Step-by-step explanation:

Given;

number of products sold in a day by toll-free sales line = 85 products

number of calls in a day = 125

The daily success rate of the sales line is given by the ratio of the total products in a day to total number of calls in a day.

The daily success rate of the sales line = total products sold / number of calls

The daily success rate of the sales line = 85 / 125

The daily success rate of the sales line = 0.68

Therefore, the daily success rate of the sales line is 0.68

7 0
3 years ago
Is 100 in greater than 3yd 1ft
wolverine [178]
1 yard = 36 inches

3 * 36 = 108

1 foot = 12 inches

108 + 12 = 120

So 3 yards and 1 foot is equal to 120 inches.

120 is greater than 100 so 3 yards and 1 foot is greater than 100 inches.
3 0
3 years ago
Read 2 more answers
If I ride a bicycle at a rate of 5m/s,how long will it take me to ride a distance of 12km at the same rate?​
Travka [436]

Step-by-step explanation:

given,velocity = 5 m/s

and distance=12×1000=12000m

now,time =?

we have , v=s/t

or, t= s/v

so,t=12000/5

2400sec.....ans

=

3 0
3 years ago
According to a study, 50 % of adult smokers started smoking before 21 years old. 5 smokers 21 years old or older are randomly se
belka [17]

Answer:

a) The probability that at least 2 of them started smoking before 21 years of age is 0.1875 = 18.75%.

b) The probability that at most 4 of them started smoking before 21 years of age is 0.96875 = 96.875%.

c) The probability that exactly 3 of them started smoking before 21 years of age is 0.3125 = 31.25%.

Step-by-step explanation:

For each smoker, there are only two possible outcomes. Either they started smoking before 21 years old, or they did not. Smokers are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

50% of adult smokers started smoking before 21 years old.

This means that p = 0.5

5 smokers 21 years old or older are randomly selected, and the number of smokers who started smoking before 21 is recorded.

This means that n = 5.

a) The probability that at least 2 of them started smoking before 21 years of age is

This is:

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.5)^{0}.(0.5)^{5} = 0.03125

P(X = 1) = C_{5,1}.(0.5)^{1}.(0.5)^{4} = 0.15625

P(X < 2) = P(X = 0) + P(X = 1) = 0.03125 + 0.15625 = 0.1875

The probability that at least 2 of them started smoking before 21 years of age is 0.1875 = 18.75%.

b) The probability that at most 4 of them started smoking before 21 years of age is

This is:

P(X \leq 4) = 1 - P(X = 5)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.5)^{5}.(0.5)^{0} = 0.03125

P(X \leq 4) = 1 - P(X = 5) = 1 - 0.03125 = 0.96875

The probability that at most 4 of them started smoking before 21 years of age is 0.96875 = 96.875%.

c) The probability that exactly 3 of them started smoking before 21 years of age is

This is P(X = 3). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{5,3}.(0.5)^{3}.(0.5)^{2} = 0.3125

The probability that exactly 3 of them started smoking before 21 years of age is 0.3125 = 31.25%.

4 0
2 years ago
. What is the equation of the line shown in the graph? *
mojhsa [17]
U have to take a pic or the graph buddy
4 0
3 years ago
Read 2 more answers
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