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photoshop1234 [79]
3 years ago
11

Answer two questions about Equations AAA and BBB:

Mathematics
2 answers:
andrew-mc [135]3 years ago
7 0

Answer:

answer is d

Step-by-step explanation:

MAVERICK [17]3 years ago
6 0

Answer:

A AND B

Step-by-step explanation:

They both have the same solution

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Sydney asked her friends to write down the number of hours they practice their instruments each week. The data is shown.
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The median in this data set is C. 5
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3 years ago
Solve each pair of equations by substituting <br><br><br> 2x + y = 3<br> 4x + 3y = 1
Usimov [2.4K]
Step: Solve
2
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−
9
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−
9
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x
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8
−
2
x
−
2
=
−
8
−
2
(Divide both sides by -2)
x
=
4

Step: Substitute
4
for
x
in
y
=
−
2
x
+
3
:
y
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−
2
x
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6 0
3 years ago
Read 2 more answers
What is the area of ABC?
notsponge [240]

Let D be the Intersection of Height of the Triangle and Base of the Triangle BC

From the Figure, We can notice that Triangle ADB is a Right angled Triangle.

We know that, In a Right angled Triangle :

\bigstar  (Hypotenuse)² = (First Leg)² + (Second leg)²

In Triangle, ADB : AB is the Hypotenuse, AD is the First leg and BD is the Second leg

Given : AB = 15 and BD = 9

Substituting the values, We get :

:\implies  (15)² = (AD)² + (9)²

:\implies  225 = (AD)² + 81

:\implies  (AD)² = 225 - 81

:\implies  (AD)² = 144

:\implies  (AD)² = (12)²

:\implies  AD = 12

We know that, In a Right angled Triangle :

\bigstar\;\;\boxed{\mathsf{Tan\theta = \dfrac{Opposite\;Side}{Adjacent\;Side}}}

Now, Consider Triangle ADC : With respect to 45° Angle, AD is the Opposite Side and DC is the Adjacent Side

:\implies \mathsf{In\;Triangle\;ADC,\;Tan45^{\circ} = \dfrac{AD}{DC}}

\mathsf{:\implies 1 = \dfrac{12}{DC}}

:\implies  DC = 12

:\implies  Total Length of the Base (BC) = BD + DC

:\implies  Total Length of the Base (BC) = 9 + 12

:\implies Total Length of the Base (BC) = 21

We know that, Area of the Triangle is given by :

\bigstar\;\;\boxed{\mathsf{Area = \dfrac{1}{2} \times Base \times Height}}

In Triangle, ABC : AD is the Height and BC is the Base

:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = \dfrac{1}{2} \times BC \times AD}

:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = \dfrac{1}{2} \times 21 \times 12}

:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = (21 \times 6)}

:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = 126}

7 0
3 years ago
The rectangle below has an area of 8x^5+12x^3+20x^2.
Y_Kistochka [10]

Answer:

The width of the rectangle is 4x^24x

2

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Step-by-step explanation:

5 0
4 years ago
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If f(x) = 3^+ 10 and g(x) = 2x - 4, find (f - g)(x).
just olya [345]

Answer:

3^x -2x +14

Step-by-step explanation:

I will assume you mean 3^x in the function f(x)

f(x) = 3^x+ 10

g(x) = 2x - 4

(f - g)(x) =  3^x+ 10  - (2x - 4)

       Distribute the minus sign

              =  3^x+ 10  - 2x + 4

              = 3^x -2x +14

8 0
3 years ago
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