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wariber [46]
3 years ago
11

Esteban has a big jar of change in his room. He has 600 coins total, and 240 of them are pennies. What percentage of the coins a

re pennies?
Mathematics
2 answers:
s2008m [1.1K]3 years ago
7 0
Well to start write it as probability. 240/600. then you would divide. and 240/600=0.4, which is 40%
Thepotemich [5.8K]3 years ago
3 0
<h2>40 % of coins are pennies.</h2>

Step-by-step explanation:

Total number of coins = 600

Total number of pennies = 240

\texttt{Percentage of the coins are pennies=}\frac{\texttt{Total number of pennies}}{\texttt{Total number of coins}}\times 100\\\\\texttt{Percentage of the coins are pennies=}\frac{240}{600}\times 100\\\\\texttt{Percentage of the coins are pennies=}\frac{240}{6}\\\\\texttt{Percentage of the coins are pennies=}\frac{120}{3}\\\\\texttt{Percentage of the coins are pennies=}40\%

40 % of coins are pennies.

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Sorry, it's late, and I'm a bad explainer.

The error is adding (2x-12) with x and 30. This is wrong because you are adding the angles inside the triangle and you are assuming that (2x - 12) is the unlabeled angle INSIDE the triangle, when it is the exterior angle/outside of the triangle.

A straight line is also 180°.

(2x - 12) + ? = 180

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If you look at the equations, and put parentheses around 30 + x, (30 + x) and (2x - 12) should be the SAME NUMBER. So you could set them equal to each other to find x. (or you could also look at the picture and see that they both need/are missing the same angle)

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3 years ago
Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK. Please explain how to find out BK​
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Answer:

Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK.

Given: △ABC, m∠B=90°

Find: AC and BK.

Short leg 90 degrees Long leg Hypotenuse

AB=12 90 BC=16 AC= ?

AK = ? 90 BK = ? AB=12

AC = SQRT (AB*AB + BC*BC) = 20 [right triangle; Pythagorean Theorem]

Similar triangles:[Note: In diagram, share two angles. Therefore share three angles]

BK / 16 = AB / AC

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BK = (3/5)16

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another answer let see this

AB^2+BC^2=AC^2

12^2+16^2=AC^2

144+256=AC^2

400=AC^2

20=AC

# be careful#

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