GEOMETRY HELP !!!!!!!!!What is the sequence of transformations that

Mathematics

1 answer:

WINSTONCH [101]3 years ago

4 0

Answer:

(1) (B) y = x and

(2) (D) 10 units to the right and 4 units up.

Step-by-step explanation:

Since we are given that ΔA'B'C' is formed after a sequence of transformations applied to ΔABC.

The first is a reflection across a line and second is a translation.

The co-ordinates of point C are (-4, -2). After reflection from the line y = x, the co-ordinates becomes (2, -4).

Also, the coordinates of point C' are (12, 0).

So, to reach point C' from point C, we should add 10 units to the x-coordinate and 4 units to the y-coordinate.

That is, the translation of 10 units right and 4 units up.

Thus, the complete transformation is

The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection across the line y = x followed by a translation 10 units right and 4 units up.

Thus, the correct answer is (1) y = x and (2) 10 units to the right and 4 units up.

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1/4 + 1/3= {Khan Academy btw}

zmey [24]

Answer: $\frac{7}{12}$

Step-by-step explanation:

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3 years ago

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djverab [1.8K]

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3 years ago

Read 2 more answers

Find the coordinates of C' after a reflection across the line

iragen [17]

<h3>Answer: (4,2)</h3>

==============================================================

Explanation:

C is at (0,0). Ignore the other points.

Reflecting over y = 1 lands the point on (0,2) because we move 1 unit up to arrive at the line of reflection, and then we keep going one more unit (same direction) to complete the full reflection transformation. I'll call this point P.

Then we reflect point P over the line x = 2 to arrive at the location Q = (4,2). Note how we moved 2 units to the right to get to the line of reflection, and then keep moving the same direction 2 more units, then we have applied the operation of "reflect over the line x = 2"

So we have started at C = (0,0), moved to P = (0,2) and then finally arrived at the destination Q = (4,2). This is the location of C' as well.

All of this is shown in the diagram below.