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zimovet [89]
3 years ago
6

43/50 equals what decimal

Mathematics
1 answer:
snow_lady [41]3 years ago
4 0
43 divided by 50 equals to 0.86
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2 = f/8 <br><br><br> f= ? <br> Pleaze helpsz me i will give you robux I promise !!
Ilia_Sergeevich [38]

Answer:

f = 16

Step-by-step explanation:

2 = f/8

Cross Multiplying, we get

f = 16

hope it helps!

8 0
3 years ago
Read 2 more answers
Find the value of PR if Q is between P and R<br> when PQ=25, PQ=2x+1, and QR=x.<br> X<br> ат<br> X=8
Eva8 [605]

Answer:

PR = 37

Step-by-step explanation:

Given

PQ = 25

PQ = 2x +1

QR = x

Required

PQ

Since Q is between the given points, then:

PR = PQ + QR

This gives:

PR = 2x + 1 + x

Collect like terms

PR = 2x + x+ 1

PR = 3x + 1

Next, solve for x

We have:

PQ = 25

PQ = 2x +1

This gives:

2x + 1 = 25

Collect like terms

2x = 25 -1

2x = 24

Divide by 2

x = 12

So:

PR = 3x + 1

PR = 3 * 12 + 1

PR = 37

7 0
2 years ago
A group of 30 students from your school is part of the audience for a TV game show. The total number of people in the audience i
s344n2d4d5 [400]

Answer:

5.3%

Step-by-step explanation:

The final probability is calculated by means of the quotient of the specific combinations and the total of total combinations

Let's start with the specific ones,

First the number of combinations of 4 of the 30 students getting a spot, i.e .:

A combinations are equal to:

nCx = n! / x! * (n-x)!

Replacing:

30C4 = 30! / (4! * 26!) = 27405

Segundo the number of combinations of the other audience members filling the other 4 (8-4) spots n = 110, 140 - 30

110C4 = 110! / (4! * 106!) = 5773185

Now the total combinations of possible 8 contestants from the audience

140C8 = 140! / (8! * 132!) = 2.98 * 10 ^ 12

Finally, the probability is equal to:

P = (30C4 * 110C4) / 140C8

replacing:

P = 27405 * 5773185 / 2.98 * 10 ^ 12

P = 0.053

Therefore the probability is 5.3%

4 0
3 years ago
Given the vector (4|3) and the transformation matrix (0|1|-1|0), which vector is the imagine after applying the transformation t
horrorfan [7]

Answer:

C.(3|-4)

Step-by-step explanation:

Given the vector:

\left[\begin{array}{ccc}4\\3\end{array}\right]

The transformation Matrix is:

\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]

The image of the vector after applying the transformation will be:

\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4\\3\end{array}\right]\\\\=\left[\begin{array}{ccc}0*4+1*3\\-1*4+0*3\end{array}\right]\\\\=\left[\begin{array}{ccc}3\\-4\end{array}\right]

The correct option is C

7 0
3 years ago
Help?,?,?,?.!.??.?.?.?.?.?.
DaniilM [7]

Answer:

Step-by-step explanation:

b(a + 1) + a = b*a + b + a = ab + b + a

1) b(2a +1 ) = b*2a + b*1 = 2ab + b  Not equivalent.

2)a + (a +1)*b = a + ab+ b     Equivalent

3) (a +1)(b+ a) = a*(b +a) + 1*(b+a) = ab+ a² +b + a  Not equivalent.

4) (a + 1)b + a = ab+ b + a   Equivalent

5) a + b(a+1) = a +ab + b Equivalent

6) a + (a +1) + b = a + a + 1 + b = 2a + 1 +b  Not equivalent.

7) a(b +1) + b = ab + a + b  Equivalent

5 0
3 years ago
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