Answer:
<h3>37.5m/s</h3>
Step-by-step explanation:
If a coal train in Montana starts from rest and accelerates at 2.5 m/s2 for 15s,let us calculate the final velocity of the train.
Use the equation of motion v = u + at where;
v is the final velocity
u is the initial velocity = 0m/s (starts from rest)
a is the acceleration = 2.5m/s²
t is the time = 15secs
Substituting the given parameters into the formula;
v = 0+(2.5)(15)
v = 0+37.5
v = 37.5m/s
Hence the final velocity of the train is 37.5m/s
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So you first multiply the fractions: 2/5 times -1/5 = -2/25; then the a's: a^2 times a equals a^3; then multiply the x's: x times x^2 equals x^3.
The answer would be -2/25a^3x^3
