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Vsevolod [243]
3 years ago
6

What happens during an Active object's animation sequence action?

Computers and Technology
1 answer:
RoseWind [281]3 years ago
4 0

Answer:

B. The Active object's animation stops looping.

Explanation:

As the new event happens, the loop tells it to happen by stopping. And hence, B is the correct option out here. Neither A or C and Nor D is the correct option. The animation does not end here, and the next event takes place. Also, the active object's animation does not change the speeds. Hence, the correct option here is certainly the B.

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Given an input array of strings (characters) s, pick out the second column of data and convert it into a column vector of data.
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Answer:

Consider the following code.

Explanation:

save the following code in read_and_interp.m

 

function X = read_and_interp(s)

[m, n] = size(s);

X = zeros(m, 1);

for i = 1:m

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% compute value based on previous and next entries in s array

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end

end

end

======================

Now you can use teh function as shown below

s = [ 'A' '0096' ; 'B' '0114' ; 'C' '9999' ; 'D' '0105' ; 'E' '0112' ];

read_and_interp(s)

output

ans =

96.000

114.000

109.500

105.000

112.000

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