Answer:
-
= 1
= 1
Explanation:
Argon atom has atomic number 18. Then, it has 18 protons and 18 electrons.
To determine the quantum numbers you must do the electron configuration.
Aufbau's principle is a mnemonic rule to remember the rank of the orbitals in increasing order of energy.
The rank of energy is:
1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7d
You must fill the orbitals in order until you have 18 electrons:
- 1s² 2s² 2p⁶ 3s² 3p⁶ : 2 + 2 + 6 + 2 + 6 = 18 electrons.
The last electron is in the 3p orbital.
The quantum numbers associated with the 3p orbitals are:
- = 1 (orbitals s correspond to = 0, orbitals p correspond to = 1, orbitals d, correspond to = 2 , and orbitals f correspond to = 3)
- can be -1, 0, or 1 (from - to + )
- the fourth quantum number, the spin can be +1/2 or -1/2
Thus, the six possibilities for the last six electrons are:
- (3, 1, -1 +1/2)
- (3, 1, -1, -1/2)
- (3, 1, 0, +1/2)
- (3, 1, 0, -1/2)
- (3, 1, 1, +1/2)
- (3, 1, 1, -1/2)
Hence, the correct choice is:
- = 1
- = 1
172.30.0.0: private network
10.20.1.0: public network
No it doesn’t count as an instrument
Answer:
int[ ][ ] X = new int[5][5];
It can also be declared and initialized this way:
int[][] X = {
{1,2,3,6,8},
{4, 5, 6, 9},
{7,5,6,8,9},
{8,5,8,8,9},
{10,2,6,8,11},
};
Explanation:
Above is a declaration of a two-dimensional array that can hold 5*5=25 int values. A java program is given below:
public class JavaTwoD{
public static void main(String args[ ]) {
// creating the 5X5 array
int[ ][ ] X = new int[5][5];
// looping through the array to add elements
for (int i = 0; i < X.length; i++) {
for (int j = 0; j < X[i].length; j++) {
X[i][j] = i * j;
}
}
Answer:
The user must specify the programming language he or she wants to use.
Explanation:
