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inessss [21]
2 years ago
9

If Mel opens his refrigerator door 36 times every day, about how many times will it be opened in April? Will the exact answer be

more than or less than the estimate? Explain
Mathematics
2 answers:
babunello [35]2 years ago
8 0
I'm ASSUMING it would be somewhere around 1,116 times in the month of April, it could be less than the estimate. the reason i say 1,116 is because 36 *how many times he opens the door per day* multiplied by 31 *the highest number of days in a month* is 1,116 times the door had been opened. It could be less because sometimes the month may include 30 days instead of 31..... i hope this helps some, i honestly have no clue.

USPshnik [31]2 years ago
6 0
1080 times in April
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What is the equation of the line that passes through the point (-6, -8) and has a slope of 1/3
ivanzaharov [21]

Answer <u>(assuming it can be in point-slope form)</u>:

y + 8 = \frac{1}{3} (x+6)

Step-by-step explanation:

With the given information, we can use the point-slope formula, y-y_1 = m (x-x_1), to write the equation of the line. Substitute values for the m , x_1, and y_1 in the formula to do so.

The m represents the slope, so substitute \frac{1}{3} in its place. The x_1 and y_1 represent the x and y values of one point the line intersects, so substitute -6 for x_1 and -8 for y_1. This gives the following answer and equation (just make sure to convert the double negatives into positives:  

y-(-8) = \frac{1}{3} (x-(-6))\\y + 8 = \frac{1}{3} (x+6)

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You would go through 4.5 bottles
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Help me plzzzzzzzzzzzzzzzz i have untel 5
mojhsa [17]

Answer:

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The height (in meters) of a projectile shot vertically upward from a point 4 m above ground level with an initial velocity of 25
Assoli18 [71]

Answer:

(a) The velocity after 2 second is 5.9 m/s

The velocity after 4 second is -13.7 m/s.

(b) The projectile reaches its maximum height  after 2.60 s of projection.

(c)The maximum height that is attained by the projectile is 37.18 m.

(d)Therefore the projectile hits the ground after 5.36 seconds of projection.

(e)The velocity of the projectile when it hits the ground is 27.03 m/s

Step-by-step explanation:

Given that, a projectile shot vertically upward from a point 4 m above the ground with a initial velocity of 25.5 m/s.

The height of the projectile after t seconds is

h=4+25.5t-4.9t^2

where h is in meter.

(a)

We use the formula

v=u+at

V= final velocity

u = initial velocity = 25.5 m/s

a = acceleration=   acceleration due to gravity= 9.8 m/s²

Since the object moves upward direction and acceleration due to gravity is downward direction. So here a= -9.8 m/s.

v(2)= 25.5+(-9.8)×2

     =25.5-19.6

     =5.9 m/s

And when t= 4

v(4)= 25.5+(-9.8)×4

    =25.5-39.2

    = -13.7 m/s

The velocity after 2 second is 5.9 m/s

The velocity after 4 second is -13.7 m/s.

(b)

At its maximum height,the velocity of the projectile is zero. i.e v=0

∴0=25.5+(-9.8)t

⇒9.8t=25.5

\Rightarrow t=\frac{25.5}{9.8}

⇒t = 2.60 s

The projectile reaches its maximum height  2.60 s after projection.

(c)

To find the maximum height, we are putting t= 2.60 in this equation h=4+25.5t-4.9t^2.

\therefore h= 4+(25.5\times 2.60)-(4.9\times 2.60^2)

     =37.18 m

The maximum height that is attained by the projectile is 37.18 m.

(d)

When the projectile hits the ground the height will be zero i.e h=0

From the equation of height we get

\therefore h=0=4+25.5t-4.9t^2

\Rightarrow 4+25.5t-4.9t^2=0

\Rightarrow t=\frac{-25.5\pm\sqrt{25.5^2-4(-4.9).4}}{2(-4.9)}

⇒t= -0.15 ,5.36

Therefore it hits the ground after 5.36 seconds of projection.

(e)

To find the velocity we use the formula v=u+at

Here v = final velocity=?

u=25.5 m/s,

t = 5.36 s

a= -9.8m/s²

v=25.5+(-9.8)5.36

 = -27.03 m/s

Negative sign denoted that the motion of the projectile is downward direction.

The velocity of the projectile when it hits the ground is 27.03 m/s.

6 0
3 years ago
Solve for x. −46 x=25
kvv77 [185]
-46 + x = 25
x = 25 + 46 = 71
5 0
2 years ago
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