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liraira [26]
3 years ago
6

How do you move 0.167 to 2 decimal places

Mathematics
2 answers:
Simora [160]3 years ago
8 0

Answer:

Two Decimal Places Rule #1: If the last digit in 0.167 is less than 5, then remove the last digit. Two Decimal Places Rule #2: If the last digit in 0.167 is 5 or more and the second to the last digit in 0.167 is less than 9, then remove the last digit and add 1 to the second to the last digit.

Step-by-step explanation:

olga2289 [7]3 years ago
3 0
You look at the second number after the decimal place if its 5 or more you round the second up and less than 5 Down so the answer is 0.17
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Olivia made 14 outfits for her dolls. Each outfit used 3/5 of fabric. If she started with 10 3/4 yards of fabric, how much did s
Zepler [3.9K]

Answer:

0.1 yards of fabric

Step-by-step explanation:

Data provided in the question:

Number of outfits made for the doll = 14

Fabric used in each outfit = \frac{3}{5} yards of fabric

Starting fabric available = 10 × \frac{3}{4} or \frac{30}{4} yards

Now,

The total fabric used in making the outfits of 14 dolls

= 14 × \frac{3}{5} yards of fabric

= \frac{42}{5} yards of fabric

Therefore,

The fabric left after making the outfits

= Fabric available in the start - Fabric used  in making the outfits

= \frac{30}{4} yards - \frac{42}{5} yards

= \frac{30\times5-42\times4}{4\times5} yards

=  \frac{150-168}{20} yards

= \frac{2}{20} yards

= 0.1 yards of fabric

5 0
3 years ago
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and t
WINSTONCH [101]

Answer:

Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.  

How long will it take for this population to grow to a hundred rodents? To a thousand rodents?

Step-by-step explanation:

Use the initial condition when dp/dt = 1, p = 10 to get k;

\frac{dp}{dt} =kp^2\\\\1=k(10)^2\\\\k=\frac{1}{100}

Seperate the differential equation and solve for the constant C.

\frac{dp}{p^2}=kdt\\\\-\frac{1}{p}=kt+C\\\\\frac{1}{p}=-kt+C\\\\p=-\frac{1}{kt+C} \\\\2=-\frac{1}{0+C}\\\\-\frac{1}{2}=C\\\\p(t)=-\frac{1}{\frac{t}{100}-\frac{1}{2}  }\\\\p(t)=-\frac{1}{\frac{2t-100}{200} }\\\\-\frac{200}{2t-100}

You have 100 rodents when:

100=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{100} \\\\2t=98\\\\t=49\ months

You have 1000 rodents when:

1000=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{1000} \\\\2t=99.8\\\\t=49.9\ months

7 0
3 years ago
Find the simple interest you are investing $200 with a 5.2% interest rate of 3 years
kipiarov [429]

Answer:

Step-by-step explanation:

Simple interest is

I=Prt, where I= interest, P=principle (initial value), r=interest rate, t=time

I=200(0.052)3

I=$31.20

5 0
3 years ago
Read 2 more answers
Pls help fast fast fast!!!​
leonid [27]

Answer:

Jesse can pack 18 books.

Step-by-step explanation:

2.4*18=43.2+5.7==48.9

you cant fit more than fifty becaue 48.9+2.4=51.3, thus 18 is your answer

3 0
3 years ago
Rewrite 40 1/4 as a decimal
Radda [10]
40.25 is 40 1/4 as a decimal
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