Write the equation in standard form for the circle that has a diameter with endpoints (11,0) and (-11,0).

Mathematics

1 answer:

morpeh [17]4 years ago

3 0

Answer:

(11-h)^2+ (0-k)^2=121

Step-by-step explanation:

(x−h)^2+(y−k^)2=r^2. this is formula for standard form I think

plug in :)

(11-h)^2+ (0-k)^2=11^2(equals 121)

the distance of the circle is 22 because if you sketch this out, the distance between the two endpoints is 22 if you count it out.This means the radius is 11 since diameter is 22

sorry if this is wrong but hope it helps

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Partial fraction decomposition<br> 20x+9/25x^2+20x+4

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Step-by-step explanation:

We have

$\frac{20x + 9}{25 {x}^{2} + 20x + 4 }$

Let's factor the denomiator first,

the denomaitor is a perfect square so we get

$\frac{20x + 9}{(5x + 2) {}^{2} }$

Now, we must think of two fractions that

$\frac{a}{(5x + 2) {}^{2} } + \frac{b}{5x + 2}$

We use a perfect square term for one fraction, then a linear one for the next, because if we set both of the denomiator to the same factor, we would get a inconsistent system.

So right now, we have

$\frac{a}{(5x + 2) { }^{2} } + \frac{b}{5x + 2} = \frac{20x +9 }{25 {x}^{2} + 20x + 4 }$