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MA_775_DIABLO [31]
2 years ago
11

Determine the ratio equivalent to cos Q.

Mathematics
1 answer:
disa [49]2 years ago
5 0
<h3>Answer:   cos(Q) = 5/13</h3>

=========================================================

Work Shown:

The triangles are similar, which means the corresponding angles are congruent. In this case, we can say angle K = angle Q. Note how K and Q are the second letters of JKL and PQR respectively. The order matters.

Because angle K = angle Q, we can use information from triangle JKL to get information about triangle PQR.

We can say the following:

cos(angle) = adjacent/hypotenuse

cos(K) = LK/JK

cos(K) = 5/13

cos(Q) = 5/13 ... plug in K = Q

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Show your work and plz help me !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
AveGali [126]

Answer:

p = 16

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

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8 0
3 years ago
What is the name of the line of reflection for the pair of figures? Enter your answer in the box. line
statuscvo [17]

Are you asking for the letter or what the line is called because if it's just the letter then it is r if it is the name then its a plane intersect.

7 0
3 years ago
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When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
1 year ago
Paco uses a spinner to select a number from 1 through 5, each with equal probability. Manu uses a different spinner to select a
lions [1.4K]
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Then 50 - 9 =  41 are the possibilities that the product of the two numbers is less than 30.

The probalility, then, is 41/50 = 0.82
7 0
3 years ago
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Indicate in standard form the equation of the line passing through the given point and having the given slope. R(4,0), m=5
liberstina [14]
First you put the equation in point slope form- Y-0= 5x - 4
Then add the zero to the 4.
Final answer: y= 5x -4
7 0
2 years ago
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