All categories

3 years ago

Determine the ratio equivalent to cos Q.

Mathematics

1 answer:

disa [49]3 years ago

5 0

<h3>Answer: cos(Q) = 5/13</h3>

=========================================================

Work Shown:

The triangles are similar, which means the corresponding angles are congruent. In this case, we can say angle K = angle Q. Note how K and Q are the second letters of JKL and PQR respectively. The order matters.

Because angle K = angle Q, we can use information from triangle JKL to get information about triangle PQR.

We can say the following:

cos(angle) = adjacent/hypotenuse

cos(K) = LK/JK

cos(K) = 5/13

cos(Q) = 5/13 ... plug in K = Q

You might be interested in

Which one of the following equations is equivalent to the equation ?<br> A<br> 6x−22=26x-22=2

mihalych1998 [28]

We simplify the equation :

2(x+3) + 5x = 34

= 2x + 6 + 5x
= 7x + 6

So, 7x + 6 = 34
x = (34-6)/7 = 4

Equation A : 6x - 22 = 2
x = (22+2)/6 = 4 (so it's equvalent).

Equation B : x/5 = 4
x = 4 x 5 = 20 (not equivalent)

Equation C :
3x - 6 = 12
x = (12+6)/3 = 6 (not equivalent)

Equation D : 6x = 18
x = 18/6 = 3 (not equivalent)

So, it's equation A

8 0

3 years ago

Einsteinium-253253253 is an element that loses about \dfrac23

Sedbober [7]

Answer:

$S(t)=450\times(1/3)^t$

Explanation:

The element is <em>einstenium-253</em>. That means that the mass number, i.e. numbrer of protons plus neutrons, of this isotope is 253, but that is not relevant to answer the question.

It is said that the element <em>loses about 2/3 of its mass every month, </em>then to find the remaining amount, every month you have to multiply by 1/3.

With that you can create a decaying function that gives a sample's mass in grams:

$Initial\text{ }mass=M_0\\ \\ Mass\text{ }after\text{ }1\text{ }month=M_0\times1/3\\ \\ Mass\text{ }after\text{ }2\text{ }months=M_0\times(1/3)^2\\ \\ Mass\text{ }after\text{ }3\text{ }months=M_0\times(1/3)^3\\ \\ Mass\text{ }after\text{ }t\text{ }months=M_0\times(1/3)^t$

Now you can replace the initial mass with 450 g and write the specific function for this sample:

$S(t)=450\times(1/3)^t$

4 0

3 years ago

Read 2 more answers

Evaluate the following<br><br> 9÷3+2 times 8-4

adelina 88 [10]

This is how I would evaluate it ... (9/3)2 +(8 - 4)

Tell me if you need the actual answer.

Hope this helped!!

8 0

3 years ago

Please help,ive been stuck on it fir two days

san4es73 [151]

The square root of 73. Since the theorem is a^2+b^2=c^2 and only works with right triangles. You take 2/2 the base so you have a right triangles with a hypotenuse if 9 and a side of 3. Then you just plug in to solve.

3 0

4 years ago

Read 2 more answers

What is the surface area??

NeTakaya

Answer:

X-32

Step-by-step explanation:

We don’t know the value of s so therefore x-32

8 0

3 years ago