"1 indicating a coupon and all other outcomes indicating no coupon"
Probability is (number of successful outcomes) / (number of possible outcomes)
Theoretical Probability of rolling a 1: 1/8
Experimental Probability of using coupons: 4/48 = 1/12
So, the experimental probability of a customer using a coupon (that is, 1/12) is smaller than the theoretical probability of rolling a 1 (that is, 1/8).
Answer:
They changed 5m into a positive when it should've stayed as a negative until you isolate the variable m at the end, making m actually equal -7.
Step-by-step explanation:
-5m - 16 = 19
-5m = 19 + 16
-5m = 35
m = 35/-5
m = -7
Step-by-step explanation:
Did you mean
Evaluate 3/2 + (-k) + (-2) where k = -5/2
= 3/2 - (-5/2) - 2
= 3/2 + 5/2 - 2
= 8/2 - 2
= 4 - 2
= 2
Answer:
I think 60 because say u do 2×3 you get 6 but do 20×3 and it's 60 so I think it's 60 so sorry if I'm wrong.