There are 17 hops in a hop, a skip, and a jump.
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How to perform changes of units?</h3>
We have the relations:
- 1 skip = 4 hops.
- 1 jump = 3 skips.
How many hops are in a hop, a skip and a jump?
So we have:
1 hop + 1 skip + 1 jump.
First, using the second relation we rewrite:
1 hop + 1 skip + 3 skips = 1 hop + 4 skips.
Now, using the first relation:
1 hop + 4 skips = 1 hop + 4*(4 hops) = 1 hop + 16 hops = 17 hops.
There are 17 hops in a hop, a skip, and a jump.
If you want to learn more about changes of units:
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Answer:
62
Step-by-step explanation:
Draw a line from the bottom of the 4 foot line straight across (horizontally) until it hits the vertical line on your left.
The two lines (the one you drew and the left vertical line) meet at right angles.
The upper figure is a rectangle.
Area = L * W
L = 5
W = 4
Area = 5 * 4
Area = 20
Now the bottom rectangle can be found the same way.
Area = L * W
L = 14
W = 3
Area = 14 * 3
Area = 42
The total area = 42 + 20
Total area = 62.
The comment was correct.
We can use 100s for ones place, 10s for tenth place and 1s for hundredth place.
Addition of 4 and 7 in the hundredth places will give 11.
Replace 10 blocks with 1 tens block.
Add this 1 to 5 and 3 which are in tens place. This will be 1+5+3 = 9.
Addition of 1 and 2 in ones places 3.
Hence, the answer is 3.91.
Answer:
2^7x4^7-8
Step-by-step explanation:
