Question

Evaluate 3 7 r + 5 8 s 7 3 ​ r+ 8 5 ​ sstart fraction, 3, divided by, 7, end fraction, r, plus, start fraction, 5, divided by, 8, end fraction, s when r = 14 r=14r, equals, 14 and s = 8 s=8s, equals, 8.

Answer 1

Answer:

Therefore the value of given expression when r = 14 and s = 8 is

$\dfrac{3}{7}\times r + \dfrac{5}{8}\times s=11$

Step-by-step explanation:

Given:

$\dfrac{3}{7}\times r + \dfrac{5}{8}\times s$

To Find:

Value of above  equation when r = 14 and s = 8

Solution:

$\dfrac{3}{7}\times r + \dfrac{5}{8}\times s$ .............Given

Put,

$r=14\\s=8$

$\dfrac{3}{7}\times r + \dfrac{5}{8}\times s=\dfrac{3}{7}\times 14 + \dfrac{5}{8}\times 8$

Now 7 × 2 = 14 and 8 will cancel each other we get

$\dfrac{3}{7}\times r + \dfrac{5}{8}\times s=3\times 2 + 5=6+5=11$

Therefore the value of given expression is

$\dfrac{3}{7}\times r + \dfrac{5}{8}\times s=11$