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Lera25 [3.4K]
3 years ago
7

I am doing test an am need help

Mathematics
1 answer:
enot [183]3 years ago
3 0

Answer:

its a

Step-by-step explanation:

< means less than and >means greather than

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Answer the question in the picture
Svet_ta [14]
<h3>Answer:</h3>
  • left picture (bottom expression): -cot(x)
  • right picture (top expression): tan(x)
<h3>Step-by-step explanation:</h3>

A graphing calculator can show you a graph of each expression, which you can compare to the offered choices.

_____

You can make use of the relations ...

... sin(a)+sin(b) = 2sin((a+b)/2)cos((a-b)/2)

... cos(a)+cos(b) = 2cos((a+b)/2)cos((a-b)/2)

... cos(a)-cos(b) = -2sin((a+b)/2)sin((a-b)/2)

Then you have ...

\dfrac{\cos{2x}-\cos{4x}}{\sin{2x}+\sin{4x}}=\dfrac{2\sin{3x}\sin{x}}{2\sin{3x}\cos{x}}=\dfrac{\sin{x}}{\cos{x}}=\tan{x}

and ...

\dfrac{\cos{2x}+\cos{4x}}{\sin{2x}-\sin{4x}}=\dfrac{2\cos{3x}\cos{x}}{-2\cos{3x}\sin{x}}=\dfrac{-\cos{x}}{\sin{x}}=-\cot{x}


6 0
3 years ago
A 6 cm long spring extends to 9 cm when a 1 kg load is suspended from it. What would be its length if a 2 kg load were suspended
vampirchik [111]

Answer:

12 cm

Step-by-step explanation:

To calculate the length of a spring with a 2 kg load, compare the displacement of a 1 kg load and adjust accordingly.

When a 1 kg load is suspended from the spring, the spring which is 6 cm stretches to 9 cm. This is 3 cm longer due to the weight. If you attach a weight which is twice as much then the displacement will be twice as much. Instead of stretching an additional 3 cm, it will stretch 2*3 = 6 cm. Add this to the length of the spring and it stretches in total 6 + 6 = 12 cm.

4 0
3 years ago
How wide is a rectangle with a length of 38 cm and 8 dm perimeter?
Lesechka [4]
Perimeter is all four sides added together, therefore.... 
 
38+38= 76

8dm= 80cm
80cm*2=160 cm

76+160= 236<span />
8 0
3 years ago
Read 2 more answers
34
Vadim26 [7]

Answer:

They are similar by the definition of similarity in terms of a dilation

Step-by-step explanation:

The given vertices of triangle ΔABC are;

A(1, 5), B(3, 9), and C(5, 3)

The vertices of triangle ΔDEF are;

D(-3, 3), E(-2, 5), and F(-1, 2)

Therefore, we get;

The length of segment, \overline{AB} = √((9 - 5)² + (3 - 1)²) = 2·√5

The length of segment, \overline{BC} = √((9 - 3)² + (3 - 5)²) = 2·√10

The length of segment, \overline{AC} = √((5 - 3)² + (1 - 5)²) = 2·√5

The length of segment, \overline{DE} = √((5 - 3)² + (-2 - (-3))²) = √5

The length of segment, \overline{EF} = √((2 - 5)² + (-1 - (-2))²) = √10

The length of segment, \overline{DF} = √((2 - 3)² + (-1 - (-3))²) = √5

∴ \overline{AB}/\overline{DE} = 2·√5/(√5) = 2

\overline{BC}/\overline{EF} = 2·√10/(√10) = 2

\overline{AC}/\overline{DF} = 2·√5/(√5) = 2

The ratio of their corresponding sides are equal and therefore;

ΔABC and ΔDEF are similar by the definition of similarity in terms of dilation.

4 0
3 years ago
Can anyone answer these 4? if so ill give 40 points. please show work!! and no long division please. , thanks!
dolphi86 [110]
54x89=4806

123x85=10,455

64x15=960

264x14=3,696
6 0
3 years ago
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