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Lelu [443]
3 years ago
8

On the first of January you place $100 into your bank account. On the first of each month after that you

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
5 0

Answer:

a) How much money is at the account at the end of March? At the end of March is $41.70

Step-by-step explanation:

please just look at the picture

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Simplify the expression.<br> (-2-2i)(-4+6i)
hoa [83]

Answer:

20 - 4i is the correct answer!

Step-by-step explanation:

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Karen, Leo, Mariah, Olivia, and Pedro bowled scores of 123, 132, 115, 124, and 131. Leo's score is lower than Karen's. Mariah go
Paraphin [41]
Mariah: 132
Pedro:124
Olivia: 123
Karen: 131
Leo:115

They way I solved this is by making a list of all the possible answers for each person, based on one fact at a time that they give you. Then, you can start looking at multiple, and start ruling things out.
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3 years ago
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Write and equation of the translated or rotated graph in general form (picture below)
WINSTONCH [101]

Answer:

The answer is hyperbola; (x')² - (y')² - 16 = 0 ⇒ answer (a)

Step-by-step explanation:

* At first lets talk about the general form of the conic equation

- Ax² + Bxy + Cy²  + Dx + Ey + F = 0

∵ B² - 4AC < 0 , if a conic exists, it will be either a circle or an ellipse.

∵ B² - 4AC = 0 , if a conic exists, it will be a parabola.

∵ B² - 4AC > 0 , if a conic exists, it will be a hyperbola.

* Now we will study our equation:

 xy = -8

∵ A = 0 , B = 1 , C = 0

∴ B² - 4 AC = (1)² - 4(0)(0) = 1 > 0

∴ B² - 4AC > 0

∴ The graph is hyperbola

* The equation xy = -8

∵ We have term xy that means we rotated the graph about

  the origin by angle Ф

∵ Ф = π/4

∴ We rotated the x-axis and the y-axis by angle π/4

* That means the point (x' , y') it was point (x , y)

- Where x' = xcosФ - ysinФ and y' = xsinФ + ycosФ

∴ x' = xcos(π/4) - ysin(π/4) , y' = xsin(π/4) + ycos(π/4)

∴ x' = x/√2 - y/√2 = (x - y)/√2

∴ y' = x/√2 + y/√2 = (x + y)/√2

* Lets substitute x' and y' in the 1st answer

∵ (x')² - (y')² - 16 = 0

∴ (\frac{x-y}{\sqrt{2}})^{2}-(\frac{x+y}{\sqrt{2}})^{2}=

 ( \frac{x^{2}-2xy+y^{2}}{2})-(\frac{x^{2}+2xy+y^{2}}{2})-16=0

* Lets open the bracket

∴ \frac{x^{2}-2xy+y^{2}-x^{2}-2xy-y^{2}}{2}-16=0

* Lets add the like terms

∴ \frac{-4xy}{2}-16=0

* Simplify the fraction

∴ -2xy - 16 = 0

* Divide the equation by -2

∴ xy + 8 = 0

∴ xy = -8 ⇒ our equation

∴ Answer (a) is our answer

∴ The answer is hyperbola; (x')² - (y')² - 16 = 0

* Look at the graph:

- The black is the equation (x')² - (y')² - 16 = 0

- The purple is the equation xy = -8

- The red line is x'

- The blue line is y'

6 0
3 years ago
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What is the prime factorization of 378?
Tcecarenko [31]
C i think, i hope that helps
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3 years ago
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Solve for a missing factor,
Eva8 [605]

Answer:

1. 32

2. 170

3. 29

Step-by-step explanation:

1. is just 10 divided by 320, which gives you 32

2. is 10 times 17 which is 170

3. you need 29 tens to get 290.

6 0
3 years ago
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