3 years ago

Please help and number the questions Giving 50 points please solve it And I won’t report

Mathematics

1 answer:

maxonik [38]3 years ago

7 0

Answer:

1. 18.84 in

2. 56.52 cm

3. 4.71 ft

4. 25.12 m

5. 37.68 ft

6. 12.56 yd

7. 43.96 in

8. 28.26 cm

9. 7.85 m

Step-by-step explanation:

$C=2\pi r$

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Special right triangles, solve for x, y and z

Alika [10]

Answer:

x=14

y=27

z=43

Step-by-step explanation:

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2 years ago

What -7 x4=36? amogus amogus amogus amogus

77julia77 [94]

Based on the given problem of -7x⁴ = 36, the solution to the equation is x = -1.5.

<h3>What is the solution to this problem?</h3>

The equation to find x is given as:

-7x⁴ = 36

Solving it gives:

-7x⁴ = 36

x⁴ = 36/-7

x⁴ = -36/7

x = ⁴√(-36/7)

x = -1.5

In conclusion, x is -1.5.

Find out more questions on solving for x at brainly.com/question/2910769

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1 year ago

Executives for a grocery store chain want to survey their employees about a new policy regarding break times. To

marusya05 [52]

Answer:

Stratified random

Step-by-step explanation:

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2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%3Cbr%3E%0Ay%3D%20x%5E%7B2%7D%20-9" id="TexFormula1" title="&#10;y= x^{2} -9" alt="&#1

svp [43]

Simple...

y= $x^{2} -9$

$y= x^{2} -9$

It's quite easy to see $x^{2} = x^{2}$

Thus, any value of x makes the equation true.

Thus, your answer.

7 0

3 years ago

It is generally believed that the mean value of the district's total SAT score distribution is equal to 1200 (the null hypothesi

g100num [7]

Answer:

The corresponding p-value, is p = 1

Step-by-step explanation:

The maximum score SAT score, n = 1,600

The mean of the district's total SAT score distribution = 1,200

The claim of one of the districts principal, is the that mean of the district's total SAT score distribution ≠ 1,200

Using proportions, we have;

p = 1,200/1,600 = 0.75

q = 1 - p = 0.25

The margin of error, E = Z√(p·q/n)

∴ E = 5% = Z×√((0.75 × 0.25)/1,600)

z = 0.05/(√((0.75 × 0.25)/1,600)) ≈ 4.61880

Therefore, the corresponding p-value, p = 1

7 0

3 years ago