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ipn [44]
3 years ago
8

What is 5.300 equivalent to

Mathematics
1 answer:
S_A_V [24]3 years ago
7 0
It is equivalent too 5.3 and 5.30
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Explain why you cannot factor the trinomial x(to the power of 2)−12x+6
Vladimir [108]

Answer:

See below

Step-by-step explanation:

You cannot find two whole number integers that give a sum of -12 and a product of 6.

-1 + -11 = -12, but (-1)(-11) = 11, which isn't 6

-2 + -10 = -12, but (-2)(-10) = 20, which isn't 6

...and so on...

4 0
2 years ago
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Taylor has 16 tacks. she buys 2 packages of 36 tacks. how many gate sale posters can she put up if she uses 4 tacks for each pos
Gemiola [76]


She can Hang up 4 posters. Because Taylor only has 16 tacks.

16/4=4

4 0
3 years ago
What is the gcf of 27 and 36
mestny [16]

The answer would be 9. 9x3=27 and 9x4=36. Although 3 fits into both, 9 is the BIGGER number that also fits into both of the numbers shown in the problem.

5 0
3 years ago
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The slope of the line that contains the points (2, 11) and (0, 5 ) is 3. Which of the following equations represents this line?
taurus [48]

Answer:

C

Step-by-step explanation:

This is your current equation: y= 3x + b. Next, plug in one of your coordinates to the equation. It doesn't matter which one. I'm going to use the second ordered pair, so it should look like this: 5 = 3(0) + b. Multiply 3 and 0 to get 5 = b. So, your equation is y = 3x + 5. The correct answer is C. Hope this helped!

7 0
3 years ago
The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t
wolverine [178]

Answer:

a) The implied differential equation is \frac{dN}{725 - N} = kdt

b) The general equation is N = 725 - C e^{-kt}

c) The particular equation is N = 725 - 325 e^{-0.49t}

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, \frac{dN}{dt} \alpha (725 - N(t))

\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt

Integrating both sides of the equation

\int {\frac{1 }{725 - N}} \, dN  = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}

When t = 0, N = 400

400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325

When t = 3,  N = 650

650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49

The equation for the population becomes:

N = 725 - 325 e^{-0.49t}

At t = 5, the population becomes:

N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697

N(5) = 700 ( to the nearest 50)

6 0
3 years ago
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