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TiliK225 [7]
3 years ago
14

Fred has 30 minutes to do a three-problem quiz. He spent 10 7/10 minutes on question a and 5 2/5 minutes on question b. How much

time did he have left for question c?
Mathematics
1 answer:
tatiyna3 years ago
3 0

Answer:Fred has 13 9/10 minutes left for question C

Step-by-step explanation:

The total time that Fred has to do the three-problem quiz is 30 minutes.

He spent 10 7/10 minutes on question A. Converting 10 7/10 minutes to improper fraction, it becomes 107/10 minutes.

He spent 5 2/5 minutes on question B. Converting 5 2/5 minutes to improper fraction, it becomes 27/5 minutes.

Total time that Fred spent on question A and question B is

107/10 + 27/5 = (107 + 54)/10

= 161/10 minutes.

The amount of time that he has left for question C would be

30 - 161/10 = (300 - 161)/10 = 139/10

= 13 9/10 minutes

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8_murik_8 [283]

Answer:

  (x, y) = (2 2/9, -1 4/9)

Step-by-step explanation:

Equate the values of y and solve for x.

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SpyIntel [72]
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What is the value of a in the equation 5a – 10b = 45, when b = 3?
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