Answer:
Volume of the cylinder = 602.88 square centimeters
Step-by-step explanation:
Given that:
Radius of cylinder = 4 cm
Height of cylinder = 12 cm
Volume of a cylinder is given by the following formula;
Volume = πr²h
Putting π = 3.14, r = 4 and h = 12 in the formula
Volume = 3.14 * (4)² * 12
Volume = 3.14 * 16 * 12
Volume = 602.88 square centimeters
Hence,
Volume of the cylinder = 602.88 square centimeters
Answer:
3.6 litres
Step-by-step explanation:
1 bottle = 450ml
8 bottles = 450 × 8
= 3600ml
1000ml = 1 litre
3600ml = 3.6 litres (3600÷1000)
Answer:
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<em>The last option matches the correct solution</em>
Step-by-step explanation:
<u>Equation Solving</u>
We have the following equation:

And it's required to solve it for r.
Solving this equation needs to perform some operations to have the r isolated from any other variables or constants.
It can be done by conveniently operating on both sides as follows:
Eliminate the denominator by multiplying by 3:

Move
to the other side by dividing by
:

Swapping sides to have r at the left side:

Finally, take the cubic root and leave r alone:
![\displaystyle r=\sqrt[3]{\frac{3V}{4\pi}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D)
The last option matches the correct solution
The proportionality constant of the given graph is k = 16.
<h3>How to find the proportionality constant of a graph?</h3>
The proportionality constant of a graph is the ratio of the y-coordinates to the x-coordinates.
Thus, it is written as k = y1/x1 = x2/y2 = ... = yn/xn
<h3>Calculation:</h3>
The given graph has the coordinates as
x = 0; y = 0 i.e., (0, 0)
x = 0.5; y = 8 i.e., (0.5, 8)
x = 1; y = 16 i.e., (1, 16)
x = 1.5; y = 24 i.e., (1.5, 24)
and so on.
Then, the ratio of y - coordinate to the x - coordinate is
k = 8/0.5 = 16
or
k = 16/1 = 16
or
k = 24/1.5 = 16
and so on.
So, the proportionality constant for the given graph is k = 16.
Learn more about the proportionality constant here:
brainly.com/question/1835116
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22 because -9 and 9 squared is 81 subtract that from 103