All categories

3 years ago

Simplify this polynomial:

Mathematics

2 answers:

Ivan3 years ago

7 0

The answer should be D.

Kipish [7]3 years ago

6 0

You add everything with the same power of x together, for exmple you have 2x^3 and the 3x^3 the x^3 is the same in both so you just add it to get 5x^3, then you do the same thing for everything collect the like terms, those who have x^2 is only -4x^2 that's the only thing left, so you write it down, and proceed to x

You might be interested in

Please help me if you can pleasee

Lerok [7]

Answer:

Slope for #17 is 3/2

Slope for #18 is -18

Step-by-step explanation:

6 0

3 years ago

Arnold is planning on painting a mural. Before painting the mural, Arnold painted the picture on a paper that is 5 inches wide a

sukhopar [10]

Answer:

0.42 ft

0.92 ft

Step-by-step explanation:

Width of mural on painting = 5 inches

Height of mural on painting = 11 inches

12 inches of the painting represents 1 foot of the mural

1 inch of the painting represenets $\dfrac{1}{12}$ foot of the mural.

$5\ \text{inches}=5\times \dfrac{1}{12}=0.42\ \text{ft}$

$11\ \text{inches}=11\times\dfrac{1}{12}=0.92\ \text{ft}$

The width of the mural is 0.42 ft and height of the mural is 0.92 ft.

5 0

3 years ago

4x^2−24x

DochEvi [55]

Answer:

See below.

Step-by-step explanation:

4x^2-24x

Find the GCF.

4 - 1, 2, 4

24 - 1, 2, 3, 4, 6, 8, 12, 24

The GCF of x^2 and x is x.

The complete GCF is 4x.

4x(x-6)

-hope it helps

4 0

3 years ago

Not sure how I am supposed to arrive to an answer

ANEK [815]

Integrating both sides once gives

$\dfrac{\mathrm d\mathbf r}{\mathrm dt}=2e^t\,\mathbf i+3e^{-t}\,\mathbf j+4e^{2t}\,\mathbf k+\mathbf c$

where $\mathbf c$ is an arbitrary constant vector. Use the initial condition to find its value:

$\dfrac{\mathrm d\mathbf r}{\mathrm dt}(0)=-\mathbf i+7\,\mathbf j=(2+c_1)\,\mathbf i+(3+c_2)\,\mathbf j+(4+c_3)\,\mathbf k$

$\implies\mathbf c_1=-3\,\mathbf i+4\,\mathbf j-4\,\mathbf k$

Integrate again:

$\mathbf r(t)=2e^t\,\mathbf i-3e^{-t}\,\mathbf j+2e^{2t}\,\mathbf k+\mathbf c_1t+\mathbf c_2$

where $\mathbf c_2$ is another arbitrary vector of constants. Use the other initial condition to determine its components:

$\mathbf r(0)=6\,\mathbf i+\mathbf j+3\,\mathbf k=(2+c_1)\,\mathbf i+(-3+c_2)\,\mathbf j+(2+c_3)\,\mathbf k$

$\implies\mathbf c_2=4\,\mathbf i+4\,\mathbf j+\mathbf k$

Then the particular solution to this ODE is

$\boxed{\mathbf r(t)=(2e^t-3t+4)\,\mathbf i+(-3e^{-t}+4t+4)\,\mathbf j+(2e^{2t}-4t+1)\,\mathbf k}$

5 0

4 years ago

How do you solve this 4x+5xy–2y?

Kitty [74]

The simplified expression of 4x + 5xy - 2y is 4x(1 + y) + y(x - 2)

<h3>How to solve the expression?</h3>

The expression is given as:

4x + 5xy - 2y

The above expression cannot be solved.

However, the expression can be grouped

So, we have:

4x + 5xy - 2y

Rewrite 5xy as 4xy + xy

So, we have:

4x + 5xy - 2y = 4x + 4xy + xy - 2y

Factorize the expression

4x + 5xy - 2y = 4x(1 + y) + y(x - 2)

Hence, the simplified expression of 4x + 5xy - 2y is 4x(1 + y) + y(x - 2)